sed 用捕获组替换行 [英] sed replace line with capture groups

问题描述

sed 是否可以用正则表达式中的捕获组替换一行?

Is it possible with sed to replace a line with capture groups from the regex?

我有这个正则表达式，请注意这是固定的，我无法更改.

I have this regex, please note that this is fixed, I cannot change it.

简单示例(.*)

这就是我想要的:

This is just a simple sample line with some text

更改为:

line with some text

我需要这样的东西:

sed '/simple sample \(.*\)/c \1'

现在输出:

1

有人知道您是否可以在 sed 中使用带有更改行功能的捕获组吗?

Anybody knows if you can use capture groups in sed with the change line function?

推荐答案

喜欢这个吗?

echo "This is just a simple sample line with some text" | \
  sed 's/simple sample \(.*\)/\n\1/;s/.*\n//'

想法很简单:用换行符前面的捕获组替换整个正则表达式匹配.然后将包括第一个换行符在内的所有内容替换为空.当然，您可以使用换行符以外的标记.

The idea is simple: replace the whole regexp match with the captured group preceded by a newline. Then replace everything up to and including the first newline with nothing. Of course, you could use a marker other than the newline.

这篇关于sed 用捕获组替换行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！