OSX sed 正则表达式删除 [英] OSX sed regex removal

问题描述

我正在尝试从 grep 搜索中删除一个字符串，尽管正则表达式看起来是正确的，但我似乎无法让 sed 工作.我也在使用 OSX，但我安装了 gnu-sed 以使事情变得更简单.

I am trying to remove a string from a grep search, and I can't seem to get sed to work, despite the regex appearing to be correct. I am also using OSX, but I installed gnu-sed to make things a little easier.

我希望以下正则表达式可以消除所有最小的确定性:

I was hoping the following regex would remove all min certainties from :

gsed -r 's/minCertainty=\"\d\.\d{1,}\"//g'

这是我正在处理的文本示例，用于上下文:

Here is an example of the text I am dealing with, for context:

<vendor="company1" minCertainty="1.0"/>
<vendor="company2" minCertainty="0.75"/>
<vendor="company3" minCertainty="0.25"/>

推荐答案

\d 用于数字是 标准正则表达式语法(基本版或扩展版).gsed -r 使用扩展的正则表达式语法，不包括 perl 扩展.所以使用 [0-9] 或 [[:digit:]] 代替.此外，您不需要对表达式中的单引号进行转义(它似乎没有伤害，但我建议不要这样做).因此，请使用其中之一:

\d for digits is a perl extension to the standard regex syntax (either the basic or extended version). gsed -r uses the extended regex syntax, and doesn't include perl extensions. So use [0-9] or [[:digit:]] instead. Also, you don't need to escape the single-quotes in the expression (it doesn't seem to hurt, but I'd recommend against it). So use one of these:

gsed -r 's/minCertainty="[0-9]\.[0-9]{1,}"//g'
gsed -r 's/minCertainty="[[:digit:]]\.[[:digit:]]{1,}"//g'

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