使用 sql 拆分字母和数字 [英] split alpha and numeric using sql

问题描述

我有一张桌子，它有 3 列.第一列是包含值(数字)和单位(百分比等)的数据，第二列是数字列，第三个是Unit column.我想要做的是从第一列中拆分数字和单位，然后将这些拆分后的数据放到其指定的列中.

I have a table and it has a 3 columns. The first column is the data that contains value(numeric) and unit(percentage and etc..), the second column is numeric column, the third is Unit column. What I want to do is split the numeric and the unit from the first column then put those split-ted data to its designated column.

这是我的桌子:

我试过这个功能:SO链接在这里...，它确实可以拆分字母和数字，但是我刚开始使用 SQL 函数，我的问题是参数必须在字符串 STRING 中，所以我所做的是将其更改为子查询但它给了我错误.

I tried this function:SO link here..., it really does splitting alpha and numeric but then I'm new in using SQL Function, my problem there is the parameter must be in string STRING, so what I did is change it to Sub Query but it gives me error.

示例代码:

SQL 函数:

create function [dbo].[GetNumbersFromText](@String varchar(2000))
returns table as return
(
  with C as
  (
    select cast(substring(S.Value, S1.Pos, S2.L) as int) as Number,
           stuff(s.Value, 1, S1.Pos + S2.L, '') as Value
    from (select @String+' ') as S(Value)
      cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
      cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
    union all
    select cast(substring(S.Value, S1.Pos, S2.L) as int),
           stuff(S.Value, 1, S1.Pos + S2.L, '')
    from C as S
      cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
      cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
    where patindex('%[0-9]%', S.Value) > 0
  )
  select Number
  from C
)

SELECT STATEMENT 和 SUB 查询:

declare @S varchar(max)
select number from GetNumbersFromText(Select SomeColm From Table_Name) option (maxrecursion 0)

顺便说一句，我使用的是 sql server 2005.

BTW, im using sql server 2005.

谢谢！

推荐答案

如果数字部分总是在开头，那么你可以这样使用:

If the numeric part is always at the beginning, then you can use this:

PATINDEX('%[0-9][^0-9]%', ConcUnit)

获取最后一位的索引.

因此:

DECLARE @str VARCHAR(MAX) = '4000 ug/ML' 

SELECT LEFT(@str, PATINDEX('%[0-9][^0-9]%', @str )) AS Number,
       LTRIM(RIGHT(@str, LEN(@str) - PATINDEX('%[0-9][^0-9]%', @str ))) As Unit

给你:

Number  Unit
-------------
4000    ug/ML

如果数字数据也包含双精度值，那么您可以使用这个:

If numeric data include double values as well, then you can use this:

SELECT LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))

获取最后一位的索引.

因此:

SELECT LEFT(@str, LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str)))

给你数字部分.

还有这个:

SELECT LEFT(@str, LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))) AS Numeric,
       CASE 
          WHEN CHARINDEX ('%', @str) <> 0 THEN LTRIM(RIGHT(@str, LEN(@str) - CHARINDEX ('%', @str)))
          ELSE LTRIM(RIGHT(@str, PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))))
       END AS Unit

同时提供数字和单位部分.

gives you both numberic and unit part.

以下是我对您发布的数据进行的一些测试:

Here are some tests that I made with the data you have posted:

输入:

DECLARE @str VARCHAR(MAX) = '50 000ug/ML'

输出:

Numeric Unit
------------
50 000  ug/ML

输入:

DECLARE @str VARCHAR(MAX) = '99.5%'

输出:

Numeric Unit
------------
99.5    

输入:

DECLARE @str VARCHAR(MAX) = '4000 . 35 % ug/ML'

输出:

Numeric     Unit
------------------
4000 . 35   ug/ML

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