如果存在依赖，编译器能否正确处理静态变量的初始化顺序? [英] Can the compiler deal with the initialization order of static variables correctly if there is dependency?

问题描述

如果存在依赖，编译器能否正确处理静态变量的初始化顺序?例如，我有

Can the compiler deal with the initialization order of static variables correctly if there is dependency? For example, I have

a.h:

struct A { static double a; };

a.cpp:

#include "a.h"
double A::a = 1;

b.h:

struct B { static double b; };

b.cpp:

#include "b.h"
#include "a.h"
double B::b = A::a;

推荐答案

在翻译单元中指定了这种初始化的顺序.未指定跨翻译单元的顺序.

Within translation units the order of such initialization is specified. Across translation units the order is not specified.

因此，在您的情况下，由于默认情况下静态初始化为零，B::b 肯定会是 0 或 1.

So in your case, since statics will get zero initialized by default, B::b will definitely be 0 or 1.

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