如何使用 swift 5 URLSession 中引入的新 Result 类型? [英] How to use new Result type introduced in swift 5 URLSession?

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问题描述

Swift 5 引入了新的 Result 类型来处理异步函数的结果.我想知道如何将这种新的结果类型用于 URLSession.

Swift 5 introduces new Result type to handle the result of an asynchronous function. I want to know the way to use this new result type for URLSession.

我有以下代码.

func getCategorByAPI()
    {
        //Base Url is from an static variable
        let url = URL(string: URLManager.aPIBaseURL+"category")!
        var request  = URLRequest(url: url)
        request.httpMethod = "GET"
        let boundary = "Boundary-\(UUID().uuidString)"
        request.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type")

        let task = URLSession.shared.dataTask(with: request as URLRequest) {
            data, response, error in

            if error != nil {
                //print("error=\(error)")
                return
            }

            do {
                let json = try JSONSerialization.jsonObject(with: data!, options: []) as? NSDictionary
                print(json)
            }catch
            {
                print(error)
            }

        }

        task.resume()
    }

如何使用 swift 5 Result 类型重写此函数?

How can i rewrite this function using swift 5 Result type?

推荐答案

您想要创建一个 enum 来指定结果中的可能情况(例如成功或失败).然后向 getCategorByAPI() 方法添加一个类型为 Result 的完成.从那里,在 url 会话中,您将调用完成处理程序,传入 .success 上的 data 上的 error.失败.

You want to create an enum that specifies the possible cases in your result (e.g. success or failure). Then you add a completion to your getCategorByAPI() method that is of type Result<Data, Error>. From there, inside url session, you will call your completion handler passing in either the data on .success or the error on .failure.

你也可以做一些很酷的事情,比如覆盖 Result 的 get() 方法并扩展 Result 来解码你的数据 :D

You can also do cool things like override Result's get() method and extend Result to decode your data :D

检查一下:

enum Result<Success, Error: Swift.Error> {
    case success(Success)
    case failure(Error)
}

// override the Result.get() method
extension Result {
    func get() throws -> Success {
        switch self {
        case .success(let value):
            return value
        case .failure(let error):
            throw error
        }
    }
}

// use generics - this is where you can decode your data
extension Result where Success == Data {
    func decoded<T: Decodable>(using decoder: JSONDecoder = .init()) throws -> T {
        let data = try get()
        return try decoder.decode(T.self, from: data)
    }
}


func getCategorByAPI(completion: (Result<Data, Error>) -> Void)
{
    // You might want to stick this into another method
    let url = URL(string: URLManager.aPIBaseURL+"category")!
    var request  = URLRequest(url: url)
    request.httpMethod = "GET"
    let boundary = "Boundary-\(UUID().uuidString)"
    request.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type")

    URLSession.shared.dataTask(with: request as URLRequest) {
        data, response, error in

        if error != nil {
            completion(.failure(error))
            return
        }

        if !(200...299).contains(httpResponse.statusCode) && !(httpResponse.statusCode == 304) {
            let httpError = // ... convert httpResponse.statusCode into a more readable error
                completion(.failure(httpError))
        }

        if let data = data {
            completion(.success(data))
        }
        }.resume()
}

我还没有测试过上述内容,但在当前项目中实现了类似的内容.以下是我阅读的一些文章,以了解如何实施:

https://www.hackingwithswift.com/articles/161/how-to-use-result-in-swift
https://medium.com/@pavlepesic/how-to-use-swift-5-result-with-codable-protocol-824c9a951af9

I haven't tested the above but have something like this implemented in a current project. Here are some articles I read to learn about how to implement:

https://www.hackingwithswift.com/articles/161/how-to-use-result-in-swift
https://medium.com/@pavlepesic/how-to-use-swift-5-result-with-codable-protocol-824c9a951af9

这篇关于如何使用 swift 5 URLSession 中引入的新 Result 类型?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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