如何在 C++ 中读取这种指针? [英] How to read this kind of pointer in c++?

问题描述

CUnknown* (*)( LPUNKNOWN pUnk, HRESULT* phr );

似乎我一直在阅读如此复杂的指针时遇到麻烦..

Seems I've always been in trouble reading such complicated pointers..

如何阅读它?如果表达式更长怎么办?

How do you read it? what if the expression even longer?

推荐答案

顺时针螺旋规则帮助我理解这样的事情.来自网站:

The Clockwise Spiral Rule helps me understand things like this. From the site:

1. 从未知元素开始，沿螺旋/顺时针方向移动；当遇到以下元素时，用相应的英文语句替换它们:

2. 继续以螺旋/顺时针方向执行此操作，直到覆盖所有标记.

1. Starting with the unknown element, move in a spiral/clockwise direction; when ecountering the following elements replace them with the corresponding english statements:

2. Keep doing this in a spiral/clockwise direction until all tokens have been covered.

总是先解决括号中的任何问题！

Always resolve anything in parenthesis first!

[X] 或 []

=> 数组 X 大小...或数组未定义大小...

=> Array X size of... or Array undefined size of...

(type1, type2)

=> 函数传递 type1 和 type2 返回...

=> function passing type1 and type2 returning...

*

=> 指向...的指针

=> pointer(s) to...

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