Java的:偏移一个byte []不执行复制操作 [英] Java: Offsetting a byte[] without performing a copy operation
问题描述
我在想,如果有可能,访问字节[]
用,而不必四处复制数据的偏差?结果
我看了阵列。*
, ByteArrayInputStream的
和 System.arraycopy
,但它们都需要分配一个新的字节[]
复制到。
我要的是一个相当于这 C ++
:
的char *缓冲区=新的char [256];
字符* buf_offset =缓冲区+ 128; //< - 无可复制
您可以通过的ByteBuffer
各地来代替。它可以前进,复制,而不进行复制切片。
的ByteBuffer真的是丑陋和反直觉。但是它被新的API JDK广泛使用,因此可以接受可能,这是一个基本的类型。
I was wondering if it is possible, access a byte[]
with an offset without having to copy data around?
I've looked at Arrays.*
, ByteArrayInputStream
and System.arraycopy
, but they all require to allocate a new byte[]
to copy to.
What I want is an equivalent to this in C++
:
char* buffer = new char[256];
char* buf_offset = buffer + 128; // <- no copy
You can pass ByteBuffer
around instead. It can be advanced, duplicated, sliced without copying.
ByteBuffer is really ugly and counter-intuitive. However it's being used extensively in new JDK APIs, so one can probably accept that it's a basic type.
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