如何初始化C字符串的二维数组的行 [英] How to initialize rows of 2D array of strings in C

问题描述

我要存储使用指针在二维字符串数组，但我很困惑与如何做到这一点。我见过的例子使用的整数数组只或使用方括号[]分配固定的内存大小。所以，我想我的初始化字符串的二维数组，这是我有：

I want to store strings in a 2D array using pointers but I'm confused with how to do it. The examples I've seen use only arrays of ints or use the brackets[] to allocate a fixed size of memory. So I'm trying to initialize my 2D array of strings and this is what I have:

char ** stringArr = (char**)malloc(/*I don't know what goes here*/);
for(i = 0; i < rows; i++)
    stringArr[i] = (char*)malloc(cols *sizeof(char));

正如你所看到的参数为我的malloc第一个电话，我坚持以什么放在那里，如果我想准确的行x个，每行的字符存储的字符串。任何帮助将是AP preciated！

As you can see the parameter for my first call of malloc, I am stuck as to what to put there if I want an exact x number of rows, where each row stores a string of chars. Any help would be appreciated!

推荐答案

这样做，因为你的指针分配一定数量的：

Do this, because you're allocating some number of pointers:

malloc(rows * sizeof(char*))

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