请求数组成员时收到错误 [英] Receiving an error when requesting members for an array

问题描述

#include <iostream>
#include <fstream>
#include <vector>
using namespace std;

int winnings[4] = {0,0,0,0};
int* p_winnings = winnings;

void CalculateGame(int* p_games);

int main()
{
    int games[6] = {12,13,14,23,24,34};
    int* p_games = games;
    int favorite_team,games_played,team1,team2,score1,score2,i;
    ifstream data("DATA11.txt");
    data >> favorite_team >> games_played;
    vector<int> standings(4);
    for (i = 0;i < 4; i++)
        standings[i] = 0;
    for (i = 0;i < games_played;i++)
    {
        data >> team1 >> team2 >> score1 >> score2;
        if (score1 > score2)
            standings[team1 - 1] += 3;
        if (score1 == score2)
            standings[team1-1]++,standings[team2-1]++;
        if (score1 < score2)
            standings[team2-1] += 3;
        for (i = 0; i < games.size();i++)
        {
            int temp1,temp2,temp;
            temp = games[i];
            temp2 = temp % 10;
            temp /= 10;
            if (temp2 == team2 && temp == team1)
                games.erase(i);
        }
    }
}

为什么当我请求的成员（如.size（）或.erase（））的阵列比赛我得到一个错误说为成员的请求的 _ 的_游戏是的非类类型为int [6]

Why when i request for a member(like .size() or .erase() ) of the array games i get an error saying "request for member __ in games which is of a non-class type int [6]"

推荐答案

普通的老C数组没有成员。所以它没有尺寸或删除。如果你的没有的希望它有成员虽然C ++ 11提供了一个名为的std ::阵列＆LT类; T，N＆GT; 可以是通过简单地做在你的情况下使用的std ::阵列＆LT; INT，6'游戏= {...} 。但是请注意，的std ::阵列不具有删除成员函数，但它有一个尺寸成员函数。

Plain old C arrays don't have members. So it has no size or erase. If you did want it to have members though, C++11 offers a class called std::array<T,N> which can be used in your case by simply doing std::array<int, 6> games = { ... }. Note however that std::array does not have an erase member function, but it has a size member function.

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