传递一个二维动态数组给函数在C ++中 [英] Passing a 2d dynamic array to a function in C++

问题描述

我有这个二维动态数组，我想将它传递给一个函数，我怎么会去这样做。

  INT **板;
        板= INT新* [boardsize]        //创建一个多维动态数组
        的for（int i = 0; I＆LT; boardsize;我++）
        {
            董事会由[i] =新的INT [boardsize]
        }
 

解决方案

  INT **板;
板= INT新* [boardsize]的for（int i = 0; I＆LT; boardsize;我++）
    董事会由[i] =新INT [大小]
 

您需要分配数组的第二深度。

要通过这个二维数组给一个函数实现它喜欢的：

  FUN1（INT **）;
 

检查以下链接二维数组实现：

的http://www.$c$cproject.com/Articles/21909/Introduction-to-dynamic-two-dimensional-arrays-in

I have this 2d dynamic array and I want to pass it to a function, How would I go about doing that

int ** board;
        board = new int*[boardsize];

        //creates  a multi dimensional dynamic array
        for(int i = 0; i < boardsize; i++)
        {
            board[i] = new int[boardsize];
        }

解决方案

int **board; 
board = new int*[boardsize]; 

for (int i = 0; i < boardsize; i++)
    board[i] = new int[size];

You need to allocate the second depth of array.

To pass this 2D array to a function implement it like:

fun1(int **);

Check the 2D array implementation on below link:

http://www.codeproject.com/Articles/21909/Introduction-to-dynamic-two-dimensional-arrays-in

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