在C＃中传递一个二维数组中的一维 [英] Passing one Dimension of a Two Dimensional Array in C#

问题描述

我已经从C迁移到C＃。
我有接受一个数组的功能。我想传递一个二维数组这个功能的一个方面

I have moved from C to C#. I have a function which accepts an array. I want to pass one dimension of a Two Dimensional array to this function.

C代码将是： -

C Code would be:-

void array_processing(int * param); 

void main()
{
  int Client_ID[3][50];
  /* Some 
     Processing 
     which fills 
     this array */
    array_processing(&Client_ID[1]);
}

现在，当我想要做在C＃一样的，我怎样才能通过这数组？
功能认定中的样子： -

Now, When I want to do same in C#, How can I pass this array? Function defination will look like:-

private void array_processing(ref int[] param);

和数组将被宣布为： -

and Array would be declared as :-

int[,] Client_ID = new int[3,50];

现在如何传递 CLIENT_ID [1] 给函数 array_processing（） ??

Now How can I pass Client_ID[1] to the function array_processing()??

这样做 array_processing（REF CLIENT_ID [ 1]）呼喊为错指标数！

By doing array_processing ( ref Client_ID[1]) shouts as "Wrong Number of Indices"!

推荐答案

您不能真正做到那。 C＃是关于它的阵列少传出，并阻止你做类似C的操作。这是一件好事。

You can't really do that. C# is less outgoing about its arrays, and prevents you from doing C-like manipulations. This is a good thing.

您有多种选择：

1. 创建一个一维数组和你的2D行复制到它


2. 使用交错数组。 - 数组的数组，这更像是什么C可以让你做

<李>

有一个array_processing重载需要一个二维数组和行号。

1. Create a 1D array and copy your 2D row to it.
2. Use a jagged array - an array of arrays, which is more like what C lets you do.

3. Have an array_processing overload that takes a 2D array and a row number.

如果您的真正的要访问二维行作为一维数组，你应该创建，将实现IList接口，并允许您访问只是一个排RowProxy'类：

If you really want to access a 2D row as a 1D array, you should create a 'RowProxy' class that will implement the IList interface and let you access just one row:

class RowProxy<T>: IList<T>
{
    public RowProxy(T[,] source, int row)
    { 
       _source = source;
       _row = row;
    }

    public T this[int col]
    {
        get { return _source[_row, col]; } 
        set { _source[_row, col] = value; }
    }

    private T[,] _source;
    private int _row;

    // Implement the rest of the IList interface
}

的其余

使用lambda表达式，将失去阵列语义，相反却是酷：

Use a lambda expression that will lose the array semantics, but is rather cool:

var ClientId = ...;

var row_5_accessor = (c=>ClientId[5, c]);

您可以使用row_5_accessor作为一个函数， row_5_accessor（3）会给你客户端Id [5,3]

You can use row_5_accessor as a function, row_5_accessor(3) will give you ClientId[5, 3]

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