根据提供的长度将重复的对象创建到数组中 [英] create duplicate objects into array based on length provided

问题描述

我想根据这样提供的长度将重复的值插入到数组中:

I want to insert duplicate values into array based on length provided like this:

var a = [{displayName: 'bar'}, {displayName:'google'}, {displayName:'mod'}];;
var dataTypesLength= 4;

输出应该是这样的:

var a = [{displayName: 'bar'},{displayName: 'bar'},{displayName: 'bar'},{displayName: 'bar'}, {displayName:'google'},{displayName:'google'},{displayName:'google'},{displayName:'google'}, {displayName:'mod'}, {displayName:'mod'}, {displayName:'mod'}, {displayName:'mod'}];

我试过了:

a = a.flatMap( word => Array.from({ dataTypesLength}).fill( word ));

但我收到打字稿错误说:Argument of type '{ dataTypesLength: any;}' 不可分配给类型为 'ArrayLike<{}>' 的参数.对象字面量只能指定已知属性，并且类型 'ArrayLike<{}>'

but I am getting typescript error saying: Argument of type '{ dataTypesLength: any; }' is not assignable to parameter of type 'ArrayLike<{}>'. Object literal may only specify known properties, and 'dataTypesLength' does not exist in type 'ArrayLike<{}>'

推荐答案

您可以将 map 与 Object.assign 一起使用，这样每个对象都有独立的引用

You can use map with Object.assign so that each object will have independent reference

var a = [{displayName: 'bar'}, {displayName:'google'}, {displayName:'mod'}];
var dataTypesLength= 4;

a= a.map(obj => { return Array(dataTypesLength).fill(null).map( e => Object.assign({}, obj)) }).flat();
console.log(a)

这篇关于根据提供的长度将重复的对象创建到数组中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！