在在C字符串数组变化特征 [英] Change characters in a string array in C

问题描述

我试图改变A字符转换为E，在一个字符串数组。但是我收到一个错误 * POS ='E'; 行。它说：MAIN.EXE已停止工作。我不明白的问题。你有什么想法？

  INT主要（无效）{
    字符* sehirler [] = {伊斯坦布尔，安卡拉，伊兹密尔，\\ 0};
    INT I;
    对于（i = 0; * sehirler [I] ='\\ 0';！++我）{
        字符* POS = sehirler [I]
        而（* POS！='\\ 0'）{
            如果（* POS =='A'）{
                的printf（％C，* POS）;
                * POS ='E'; // ERRROR
            }
            POS ++;
        }
    }
    返回0;
}
 

解决方案

你的是不是一个字符串数组，它是指向字符串数组，你不能改变字符串。

要使它成为一个数组试试这个

  INT主（INT ARGC，CHAR * ARGB []）
{
    炭sehirler [4] [9] = {伊斯坦布尔，安卡拉，密尔，};
    / * ^^
     * | | __在伊斯坦布尔`字符数'+'\\ 0'
     * | _数组中的字符串数
     * /
    INT I;
    对于（i = 0; * sehirler [I] ='\\ 0';！++我）
    {
        字符* POS = sehirler [I]
        而（* POS！='\\ 0'）
        {
            如果（* POS =='A'）
            {
                的printf（％C，* POS）;
                * POS ='E'; // ERRROR
            }
            POS ++;
        }
    }
    返回0;
}
 

您可能需要与分配空间的malloc（），然后用的strcpy（）制作的副本字面值，那么副本将是修改的。

I try to change 'a' characters into 'e', in a string array. But I receive an error *pos = 'e'; line. It says "Main.exe has stopped working". I could not understand the problem. Do you have any idea?

int main(void) {
    char *sehirler[] = { "Istanbul", "Ankara", "Izmir", "\0" };
    int i;
    for (i = 0; *sehirler[i] != '\0'; ++i) {
        char *pos = sehirler[i];
        while (*pos != '\0') {
            if (*pos == 'a') {
                printf("%c", *pos);
                *pos = 'e';          //ERRROR
            }
            pos++;
        }
    }
    return 0;
}

解决方案

Yours is not a string array, it's an array of pointers to string literals, and you can't change string literals.

To make it an array try this

int main(int argc, char *argb[])
{
    char sehirler[4][9] = {"Istanbul", "Ankara", "Izmir", ""};
    /*            ^  ^
     *            |  |__ Number of characters in `Istanbul' + '\0'
     *            |_ Number of strings in the array
     */
    int   i;
    for (i = 0 ; *sehirler[i] != '\0' ; ++i)
    {
        char *pos = sehirler[i];
        while (*pos != '\0')
        {
            if (*pos == 'a')
            {
                printf("%c", *pos);
                *pos = 'e';          //ERRROR
            }
            pos++;
        }
    }
    return 0;
}

you might need to allocate space with malloc() and then use strcpy() to make a copy of the literals, then the copy will be modifiable.

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