＆QUOT;复制和QUOT;数组中的元素，以成＆QUOT; INT＆QUOT;？ C [英] "copy" elements of array in order into an "int"? C

问题描述

这可能是一个非常简单的问题，但我需要复制在阵列两个int值[0]和阵列[1]为一个整数。

It may be a really simple question, but I need to copy two int values that are in array[0] and array[1] into a single integer.

作为实例，如果阵列[0] = 1和阵列[1] = 6，我需要的整数等于16。
阵列的任何元件具有范围从0到9。

As instance if array[0]=1 and array[1]=6, I need the integer to be equal to "16". Any element of the array has a range from 0 to 9.

什么机会做我有吗？
谢谢了很多！

What chances do I have? Thank you a lot!

推荐答案

请问阵列[0]总是重新present 10的位置和阵列[1]随时重新present 1的地方吗？将阵列[0]或阵列[1]曾经有大于9或小于0的值？会不会有永远是一个数组[2]或数组[3]重新present 3位或4位数字？

Does array[0] always represent the 10's place and array[1] always represent the 1's place? Will array[0] or array[1] ever have a value greater than 9 or less than 0? Will there ever be an array[2] or an array[3] to represent a 3 digit or a 4 digit number?

如果回答上述问题是是，否，否，那么是不是答案简单的算术题？

If the answer to the above questions are Yes, No, and No, then isn't the answer simple arithmetic?

int result = (array[0] * 10) + array[1];

如果数据不是pre范围检查的，那么你就需要补充的一步。即使数据是pre范围检查的，你应该考虑补充反正这一步，使多余的肯定。

If the data isn't pre range-checked, then you'll need to add that step. Even if the data IS pre range-checked, you should consider adding that step anyway to make extra sure.

'10'也是一个幻数在上述的例子。或许，这将是明智的，不是硬code 10，但它的基础关闭阵列的大小。考虑在有数组[2]的情况。 。 。数组[N]。然后呢？

'10' is also a magic number in the above example. It would probably be wise to not hard-code 10, but base it off of the size of the array. Consider the case where there IS an array[2] . . . array[n]. What then?

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