之间的真正区别＆QUOT; INT＆QUOT;和＆QUOT; unsigned int类型＆QUOT; [英] The real difference between "int" and "unsigned int"

问题描述

INT

32位int数据类型可以在范围内举行的整数值
 2,147,483,648到2,147,483,647。您也可以参考此数据类型
 作为签署int或签名。

The 32-bit int data type can hold integer values in the range of −2,147,483,648 to 2,147,483,647. You may also refer to this data type as signed int or signed.

unsigned int类型

32位无符号整型数据
 类型可以在0范围内持有整数值4,294,967,295。您
 也可参考此数据类型简单地作为无符号。

The 32-bit unsigned int data type can hold integer values in the range of 0 to 4,294,967,295. You may also refer to this data type simply as unsigned.

好吧，但是，在实践中：

Ok, but, in practice:

int x = 0xFFFFFFFF;
unsigned int y = 0xFFFFFFFF;
printf("%d, %d, %u, %u", x, y, x, y);
// -1, -1, 4294967295, 4294967295

没有区别，O.o.我有点糊涂了。

no difference, O.o. I'm a bit confused.

推荐答案

呵呵。在这里你有一个隐式转换，因为你告诉的printf 期望是什么类型的。

Hehe. You have an implicit cast here, because you're telling printf what type to expect.

试试这个关于大小，而不是：

Try this on for size instead:

unsigned int x = 0xFFFFFFFF;
int y = 0xFFFFFFFF;

if (x < 0)
    printf("one\n");
else
    printf("two\n");
if (y < 0)
    printf("three\n");
else
    printf("four\n");

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