参数警告:截断值大小为 32 以匹配目标大小 [英] Parameter warning: truncated value with size 32 to match size of target

问题描述

我有一个参数如下:

parameter PARAM = 7'd69;

当我尝试将该值分配给下面的寄存器时:

When I try to assign that value to the register below:

reg [6:0] r;

像这样:

r <= PARAM;

我收到综合警告:

警告(10230):...截断了大小为 32 的值以匹配目标的大小(7)

我认为这是因为 PARAM 被解释为一个整数，因为它被定义为一个 参数.有没有办法将 PARAM 定义为 7 位宽?

This I assume is because PARAM is being interpreted as an integer because it is defined as a parameter. Is there any way to define PARAM as 7 bits wide?

我总是可以将其作为 7 位输入传递给我的模块，但我想知道是否有更优雅的解决方案.

I could always pass this in as a 7-bit input to my module, but I was wondering if there is a more elegant solution.

推荐答案

您可以定义参数如下:

parameter [6:0]PARAM = 7'd69;

这样你就告诉你的编译器 PARAM 大小是 7 位.

That way you're telling your compiler that PARAM size is 7 bits.

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