这个 C++ 代码如何在没有结束返回语句的情况下编译? [英] How does this C++ code compile without an end return statement?

问题描述

我遇到了以下编译良好的代码(使用 Visual Studio 2005):

I came across the following code that compiles fine (using Visual Studio 2005):

SomeObject SomeClass::getSomeThing()
{
    for each (SomeObject something in someMemberCollection)
    {
        if ( something.data == 0 )
        {
            return something;
        }
    }
    // No return statement here
}

如果方法末尾没有 return 语句，为什么会编译?

Why does this compile if there is no return statement at the end of the method?

推荐答案

这是为了支持与 C 的向后兼容性，C 并不严格要求从所有函数返回.在这些情况下，您只剩下返回位置(堆栈或寄存器)中的最后一个值.

This is to support backwards compatibility with C which did not strictly require a return from all functions. In those cases you were simply left with whatever the last value in the return position (stack or register).

如果这是在没有警告的情况下编译的，尽管您可能没有将错误级别设置得足够高.大多数编译器现在都会对此发出警告.

If this is compiling without warning though you likely don't have your error level set high enough. Most compilers will warn about this now.

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