如何反序列化 XML 元素的编号数组 [英] How to deserialize a numbered array of XML elements

问题描述

我需要反序列化以下 XML:

I need to deserialize the following XML:

<TIMEWINDOWS>
    <NUMBER>10</NUMBER>
    <NO0>
        <FROM>22-11-2013 08:00:00</FROM>
        <TO>22-11-2013 11:59:00</TO>
    </NO0>
    <NO1>
        <FROM>22-11-2013 12:00:00</FROM>
        <TO>22-11-2013 15:59:00</TO>
    </NO1>
    <NO2>
        <FROM>23-11-2013 08:00:00</FROM>
        <TO>23-11-2013 11:59:00</TO>
    </NO2>
    <NO3>
        <FROM>23-11-2013 12:00:00</FROM>
        <TO>23-11-2013 15:59:00</TO>
    </NO3>
    ...
</TIMEWINDOWS>

我需要的输出是 TimeWindow 对象的集合(列表、数组等等)，例如:

The output that I require is a collection (list, array, whatever) of TimeWindow objects, for example:

public class TimeWindow
{
    public string From { get; set; }
    public string To { get; set; }
}

是否有处理 NO0、NO1、NO2、... 元素的标准方法?我总是可以构建自己的解析器，但我更喜欢使用标准方法，例如 System.Xml.Serialization.XmlSerializer.

Is there a standard way to handle the NO0, NO1, NO2, ... elements? I can always build my own parser, but I would much prefer to use a standard approach, such as System.Xml.Serialization.XmlSerializer.

推荐答案

这种格式相当疯狂.不幸的是，这意味着您需要使用 XDocument 或 XmlDocument 手动解析 xml.让我们使用前者，因为它更容易:

The format of this is quite crazy. Unfortunately this means you will need to parse the xml manually with XDocument or XmlDocument. Lets use the former as it is easier:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.Linq;

namespace Xmlarrayload
{
    class Program
    {
        static void Main(string[] args)
        {
            var document = XDocument.Parse(@"<TIMEWINDOWS>
    <NUMBER>4</NUMBER>
    <NO0>
        <FROM>22-11-2013 08:00:00</FROM>
        <TO>22-11-2013 11:59:00</TO>
    </NO0>
    <NO1>
        <FROM>22-11-2013 12:00:00</FROM>
        <TO>22-11-2013 15:59:00</TO>
    </NO1>
    <NO2>
        <FROM>23-11-2013 08:00:00</FROM>
        <TO>23-11-2013 11:59:00</TO>
    </NO2>
    <NO3>
        <FROM>23-11-2013 12:00:00</FROM>
        <TO>23-11-2013 15:59:00</TO>
    </NO3>
</TIMEWINDOWS>");

            int number = int.Parse(document.Root.Element("NUMBER").Value);
            TimeWindow[] windows = (TimeWindow[])Array.CreateInstance(typeof(TimeWindow), number);

            for (int i = 0; i < number; i++)
            {
                var element = document.Root.Element(string.Format("NO{0}", i));
                TimeWindow window = new TimeWindow
                {
                    //it is extremely important to use the correct culture (invariant) to parse the dates.
                    To = DateTime.ParseExact(element.Element("TO").Value, "dd-MM-yyyy HH:mm:ss", System.Globalization.CultureInfo.InvariantCulture.DateTimeFormat),
                    From = DateTime.ParseExact(element.Element("FROM").Value, "dd-MM-yyyy HH:mm:ss", System.Globalization.CultureInfo.InvariantCulture.DateTimeFormat)
                };
                windows[i] = window;
            }
        }
    }

    public class TimeWindow
    {
        public DateTime From { get; set; }
        public DateTime To { get; set; }
    }
}

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