如何在 xsl 模板中匹配这个或那个? [英] How to match this OR that in an xsl template?

问题描述

在我的 Sharepoint fldtypes_custom.xsl 文件中，我有这个代码，它运行良好.但是，我想在三个或四个相似的字段上使用相同的代码.

In my Sharepoint fldtypes_custom.xsl file, I have this code, which works perfectly. However, I want to use the same code on three or four similar fields.

有没有一种方法可以匹配同一个模板中名为 status1 OR status2, OR status3 的字段?现在我必须拥有这段代码的三个副本，唯一的区别是 fieldref 名称.我想合并代码.

Is there a way I can match fields named status1 OR status2, OR status3 in the same template? Right now I have to have three copies of this block of code where the only difference is the fieldref name. I would like to consolodate the code.

<xsl:template match="FieldRef[@Name='status1']" mode="body">
    <xsl:param name="thisNode" select="."/>
    <xsl:variable name="currentValue" select="$thisNode/@status1" />
    <xsl:variable name="statusRating1">(1)</xsl:variable>
    <xsl:variable name="statusRating2">(2)</xsl:variable>
    <xsl:variable name="statusRating3">(3)</xsl:variable>

    <xsl:choose>
        <xsl:when test="contains($currentValue, $statusRating1)">
            <span class="statusRatingX statusRating1"></span>
        </xsl:when>
        <xsl:when test="contains($currentValue, $statusRating2)">
            <span class="statusRatingX statusRating2"></span>
        </xsl:when> 
        <xsl:when test="contains($currentValue, $statusRating3)">
            <span class="statusRatingX statusRating3"></span>
        </xsl:when> 
        <xsl:otherwise>
            <span class="statusRatingN"></span>
        </xsl:otherwise>                    
    </xsl:choose>
</xsl:template> 

推荐答案

有没有办法匹配名为 status1 OR status2, OR status3 的字段在同一个模板中?

Is there a way I can match fields named status1 OR status2, OR status3 in the same template?

使用:

<xsl:template match="status1 | status2 | status3">
  <!-- Your processing here -->
</xsl:template>

但是，我从提供的代码中看到，字符串 "status1"、"status2" 和 "status3" 不是元素名称——它们只是 FieldRef 元素的 Name 属性的可能值.

However, I see from the provided code, that the strings "status1", "status2" and "status3" aren't element names -- they are just possible values of the Name attribute of the FieldRef element.

在这种情况下，您的模板可能是:

<xsl:template match="FieldRef
     [@Name = 'status1' or @Name = 'status2' or @Name = 'status3']">
  <!-- Your processing here -->
</xsl:template>

如果 Name 属性有多种可能的值，可以使用以下缩写:

In case there are many possible values for the Name attribute, one can use the following abbreviation:

<xsl:template match="FieldRef
     [contains('|status1|status2|staus3|', concat('|',@Name, '|'))]">
  <!-- Your processing here -->
</xsl:template>

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