反序列化许多子节点以添加对对象的引用 xStream java [英] deserializing many child nodes to add references to objects xStream java

问题描述

我正在对下图进行序列化:

Hi I'm de serializing the following graph:

<grafo>
 <nodo id="1">
   <child id="2"/>
 </nodo>
 <nodo id="2">
   <child id="3"/>
   <child id="4"/>
 </nodo>
 <nodo id="3">
   <child id="4"/>
 </nodo>
 <nodo id="4">
   <child id="1"/>
 </nodo>

我需要将子节点与图列表中其他节点的引用链接，这意味着在解组过程中，我不能只创建一个新节点并使用给我读者的属性设置它的 id，我需要它与图上已经存在的节点共享它的属性，以便能够做到这一点，我在 GraphConverter 类中尝试使用以下函数:

I need to link the child nodes with references of other nodes in the graph List, that means that in the unmarshalling process I can't just create a new Node and set it's id with the atribute that gives me the reader, I need it to share it's atributes with the nodes that are already on the graph, to be able to do that I was trying with the following function in a GraphConverter class:

public Object unmarshal(HierarchicalStreamReader reader,UnmarshallingContext arg1) {
    Grafo graph= new Grafo();
    ArrayList<ArrayList<String>> handlechilds= new ArrayList<ArrayList<String>>();
     while (reader.hasMoreChildren()) 
     {
         reader.moveDown();
         Nodo node= new Nodo(reader.getAttribute("id"));
         graph.nodos.add(node);
         reader.moveDown();
         //reader.getAttribute("id") ->> this just gives me the value of the fisrt node but not the anothers!!
         reader.moveUp();
         reader.moveUp();
     }
    return graph;
}

我想保存边的值并在另一个中添加引用，以便在图形上迭代，但我意识到当读者只返回一个孩子时，我需要所有这些.

I was thinking to save the values of the edges and add the references in another for that iterates over the graph, but I realized that when the reader just returns one of the childs, and I need all of them.

推荐答案

阅读对象引用在 XStream 中.

Read about Object references in XStream.

xstream.setMode(XStream.ID_REFERENCES);

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