在 Anylogic 中只允许固定数量的代理定期通过队列块 [英] Allow only a fixed number of agents to pass through a queue block periodically in Anylogic

问题描述

我同时使用 Queue 和 Hold 块，在所有代理到达 Queue 块之前，hold 一直处于阻塞状态.

I am using a Queue and hold block together, where the hold remains blocked until all the agents arrive at the Queue block.

如何更改它并希望在固定的时间间隔(例如每 3 分钟)只允许固定数量的代理(例如 5 个代理)?我的队列和保持块的当前属性:

How to change it and want to allow only a fixed number of agents (say 5 agents) at fixed intervals of time(say every 3 minutes)? Current properties of my Queue and hold block:

queue_block_properties

queue_block_properties

hold_block_properties

hold_block_properties

推荐答案

创建重复时间为 3 分钟的循环事件.还要创建一个变量，您可以将其命名为 count，类型为 int.

Create a cyclic event with recurrence time 3 minutes. Also create a variable which you can name count of type int.

在事件操作字段中写入:

In the event action field write:

count = 0;
hold.unblock();

然后，在保持块的 On enter 字段中写入以下内容:

Then, in the On enter field of the hold block write the following:

count++;
if( count == 5 ) {
   self.block();
}

我唯一的问题是，您是否希望每 3 分钟就有 5 个特工离开，或者他们晚一点到达是否可以.换句话说，如果 3 分钟后，队列中只有 3 个代理，他们是否离开并保持畅通，以防在下一个周期之前又有 2 个代理到达?还是保持块立即再次阻塞?

The only question that I have is whether you want every 3 minutes to have exactly 5 agents leave or whether it's okay if they arrive a bit later. In other words if after 3 minutes, there are only 3 agents in the queue, do they leave and the hold remains unblocked in case another 2 arrive before the next cycle? Or does the hold block blocks again immediately?

在我提供的解决方案中，如果在循环时间发生时少于 5 个，然后新的代理在下一个循环之前到达，他们可以通过.

In the solution I provided, if there are less than 5 at the cycle time occurrence, and then new agents arrive before the next cycle, they can pass.

否则，例如创建一个名为 target 的新变量并在事件操作中写入以下内容:

Otherwise, create a new variable called target for example and write the following in the event action:

count= 0;

if( queue.size() >= 5 ) {
    target = 5;
    hold.unblock();

}

else if ( queue.size() > 0 ) {
    target = queue.size();
    hold.unblock();
}

在保留的输入处，写:

count++;

if( count == target ) {
self.block();
target = 0;
}

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