如何在 JavaScript 函数中传递第 n 个可选参数而不传递先前的参数? [英] How to pass the nth optional argument without passing prior arguments in JavaScript functions?

问题描述

假设我们有一个如下所示的函数，我想对第一个参数 a 使用默认值，为第二个参数 b 使用自定义值.

So imagine we got a function like below, and I want to use the default value for the first parameter a and a custom value for second parameter b.

const func = (a = 1 , b = 2) => {
    console.log("a is equal to " + a, " and b is equal to " + b)
}

我只想为参数 b 传递一个值.像这样:

I want to just pass one value for parameter b. something like this:

func(b : 7);
// I want it to print: a is equal to 1 and b is equal to 7

如何在 JavaScript 中实现它?

How can I achieve it in JavaScript?

推荐答案

您修改函数以接收一个对象，然后在该对象中您还可以为某些属性(如 a 和 b)定义默认值.

You modify your function to receive an object and then inside that object you can also define default values for some properties like a and b.

const func = ({ a = 1, b = 2 }) => {
  console.log("a is equal to " + a, " and b is equal to " + b)
}

func({b: 3})

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