如果传递给函数，则确定数组的大小 [英] determine size of array if passed to function

问题描述

如果传递给另一个函数(未传递大小)，是否可以确定数组的大小?数组初始化为 int array[] = { XXX } ..

Is it possible to determine the size of an array if it was passed to another function (size isn't passed)? The array is initialized like int array[] = { XXX } ..

我知道不可能执行 sizeof ，因为它会返回指针的大小.. 我问的原因是因为我需要在传递数组的另一个函数中运行 for 循环.我试过类似的东西:

I understand that it's not possible to do sizeof since it will return the size of the pointer .. Reason I ask is because I need to run a for loop inside the other function where the array is passed. I tried something like:

for( int i = 0; array[i] != NULL; i++) {
........
}

但我注意到在数组的近端，array[i] 有时包含垃圾值，如 758433，这不是数组初始化中指定的值.

But I noticed that at the near end of the array, array[i] sometimes contain garbage values like 758433 which is not a value specified in the initialization of the array..

推荐答案

其他答案忽略了 C++ 的一个特性.您可以通过引用传递数组，并使用模板:

The other answers overlook one feature of c++. You can pass arrays by reference, and use templates:

template <typename T, int N>
void func(T (&a) [N]) {
    for (int i = 0; i < N; ++i) a[i] = T(); // reset all elements
}

那么你可以这样做:

int x[10];
func(x);

但请注意，这只适用于数组，不适用于指针.

but note, this only works for arrays, not pointers.

然而，正如其他答案所指出的，使用 std::vector 是更好的选择.

However, as other answers have noted, using std::vector is a better choice.

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