比较两个对象数组并删除第二个对象数组中具有相同属性值的项目 [英] Compare two arrays of objects and remove items in the second one that have the same property value

问题描述

我需要做的就是比较两个对象数组并删除第二个对象中具有相同属性值的项目.例如:

All I need to do is compare two arrays of objects and remove items in the second one that have the same property value. For example:

var a = [{'name':'bob', 'age':22}, {'name':'alice', 'age':12}, {'name':'mike', 'age':13}];
var b = [{'name':'bob', 'age':62}, {'name':'kevin', 'age':32}, {'name':'alice', 'age':32}];

function remove_duplicates(a, b) {
    for (var i = 0, len = a.length; i < len; i++) {
        for (var j = 0, len = b.length; j < len; j++) {
            if (a[i].name == b[j].name) {
                b.splice(j, 1);
            }
        }
    }

    console.log(a);
    console.log(b);

}

console.log(a);
console.log(b);

remove_duplicates(a,b);

我不明白为什么这不起作用，而是给出:

I cannot understand why this does not work and instead gives:

Uncaught TypeError: Cannot read property 'name' of undefined

我期望的是 b 中的以下内容:

What I expected was the following content in b:

[{'name':'kevin', 'age':32}];

推荐答案

FIDDLE

 for (var i = 0, len = a.length; i < len; i++) { 
        for (var j = 0, len2 = b.length; j < len2; j++) { 
            if (a[i].name === b[j].name) {
                b.splice(j, 1);
                len2=b.length;
            }
        }
    }

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