将两个数组与对象进行比较，并使用不匹配的对象创建新数组 [英] Compare two Arrays with Objects and create new array with unmatched objects

问题描述

我有以下两个 Javascript 数组:

I have the following two Javascript arrays:

const array1 = [{ id: 1}, { id: 2 }, { id: 3 }, { id: 4}];
const array2 = [{ id: 1}, { id: 3 }];

我现在想要一个新的数组 array3 ，它只包含不在 array2 中的对象，所以:

I now want a new array array3 that contains only the objects that aren't already in array2, so:

const array3 = [{ id: 2}, { id: 4 }];

我尝试了以下操作，但它返回所有对象，当我将条件更改为 === 时，它返回 array2 的对象.

I have tried the following but it returns all objects, and when I changed the condition to === it returns the objects of array2.

const array3 = array1.filter(entry1 => {
  return array2.some(entry2 => entry1.id !== entry2.id);
});

有什么想法吗?欢迎使用 ES6

Any idea? ES6 welcome

推荐答案

你可以颠倒比较(相等而不是不相等)并返回 some 的否定结果.

You could reverse the comparison (equal instead of unqual) and return the negated result of some.

const
    array1 = [{ id: 1 }, { id: 2 }, { id: 3 }, { id: 4 }],
    array2 = [{ id: 1 }, { id: 3 }],
    array3 = array1.filter(entry1 => !array2.some(entry2 => entry1.id === entry2.id));
    //                               ^                                ^^^

console.log(array3);

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