是 sig_atomic_t 和 std::atomic<>可互换? [英] Are sig_atomic_t and std::atomic<> interchangable?
问题描述
根据标题.我可以在信号处理程序中使用 std::atomic<> 还是 sig_atomic_t 提供其他编译器功能?
As per the title. Can I use std::atomic<> in a signal handler or does sig_atomic_t provide other compiler features?
推荐答案
n3376 1.9/6
n3376 1.9/6
当抽象机的处理因收到信号而中断时，对象的值都不是
When the processing of the abstract machine is interrupted by receipt of a signal, the values of objects which are neither
——类型为 volatile std::sig_atomic_t 或
— of type volatile std::sig_atomic_t nor
——无锁原子对象(29.4)
— lock-free atomic objects (29.4)
在信号处理程序执行期间未指定，并且任何不在其中任何一个中的对象的值处理程序修改的这两个类别变为未定义.
are unspecified during the execution of the signal handler, and the value of any object not in either of these two categories that is modified by the handler becomes undefined.
无锁 29.4/1,2
Lock-free 29.4/1,2
<块引用>
ATOMIC_..._LOCK_FREE 宏指示相应原子类型的无锁属性，其中有符号和无符号的变体组合在一起.这些属性也适用于相应的(部分)原子模板的特化.值 0 表示类型从不无锁.一个值1 表示这些类型有时是无锁的.值为 2 表示类型始终是无锁的.
The ATOMIC_..._LOCK_FREE macros indicate the lock-free property of the corresponding atomic types, with the signed and unsigned variants grouped together. The properties also apply to the corresponding (partial) specializations of the atomic template. A value of 0 indicates that the types are never lock-free. A value of 1 indicates that the types are sometimes lock-free. A value of 2 indicates that the types are always lock-free.
函数atomic_is_lock_free (29.6) 指示对象是否是无锁的.在任何给定的程序中执行，无锁查询的结果对于所有同类型的指针应该是一致的.
The function atomic_is_lock_free (29.6) indicates whether the object is lock-free. In any given program execution, the result of the lock-free query shall be consistent for all pointers of the same type.
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