如何在不回显的情况下从 shell 脚本获取密码 [英] How to get a password from a shell script without echoing

问题描述

我有一个脚本可以自动执行需要访问密码保护系统的过程.该系统通过接受用户密码作为参数的命令行程序进行访问.

I have a script that automates a process that needs access to a password protected system. The system is accessed via a command-line program that accepts the user password as an argument.

我想提示用户输入他们的密码，将其分配给一个 shell 变量，然后使用该变量来构建访问程序的命令行(这当然会产生我将处理的流输出).

I would like to prompt the user to type in their password, assign it to a shell variable, and then use that variable to construct the command line of the accessing program (which will of course produce stream output that I will process).

我是 Bourne/Bash 中相当称职的 shell 程序员，但我不知道如何接受用户输入而不让它回显到终端(或者可能使用*"字符回显).

I am a reasonably competent shell programmer in Bourne/Bash, but I don't know how to accept the user input without having it echo to the terminal (or maybe having it echoed using '*' characters).

有人可以帮忙吗?

推荐答案

这是另一种方法:

#!/bin/bash
# Read Password
echo -n Password: 
read -s password
echo
# Run Command
echo $password

read -s 将为您关闭回显.只需将最后一行的 echo 替换为您要运行的命令即可.

The read -s will turn off echo for you. Just replace the echo on the last line with the command you want to run.

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