如何从shell脚本中的密码，而不回显 [英] How to get a password from a shell script without echoing

问题描述

我有自动化需要密码保护系统访问的过程的脚本。该系统是通过接受用户的密码作为参数的命令行程序访问。

I have a script that automates a process that needs access to a password protected system. The system is accessed via a command-line program that accepts the user password as an argument.

我想提示用户需要键入密码，并将其分配给一个shell变量，然后使用该变量来构建访问程序的命令行（这当然会产生流输出的，我会处理） 。

I would like to prompt the user to type in their password, assign it to a shell variable, and then use that variable to construct the command line of the accessing program (which will of course produce stream output that I will process).

我在伯恩/猛砸一个合理的主管外壳程序员，但我不知道如何接受用户的输入，而无需其显示到终端（或者有它采用呼应​​字符）。

I am a reasonably competent shell programmer in Bourne/Bash, but I don't know how to accept the user input without having it echo to the terminal (or maybe having it echoed using '*' characters).

任何人都可以在这方面帮助？

Can anyone help with this?

推荐答案

下面是另一种方式来做到这一点：

Here is another way to do it:

#!/bin/bash
# Read Password
echo -n Password: 
read -s password
echo
# Run Command
echo $password

的读-S 将关闭回声你。只需更换回声与您要运行该命令的最后一行。

The read -s will turn off echo for you. Just replace the echo on the last line with the command you want to run.

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