如何在 Matlab 中使用 Unix 时间戳? [英] How to work with Unix timestamps in Matlab?
问题描述
我有一些带有 Unix 时间戳的数据文件(在这种情况下,自 1970 年 1 月 1 日 00:00 UTC 以来的毫秒数).我想在 Matlab 中将这些转换为人类友好的日期/时间字符串(例如 31-Aug-2012 11:36:24).在 Matlab 中是否有一种简单的方法可以做到这一点,还是我最好使用外部库(例如 java.text.SimpleDateFormat)?
I have some data files with Unix timestamps (in this case, number of milliseconds since Jan 1, 1970 00:00 UTC). I would like to convert these to human-friendly date/time strings (e.g. 31-Aug-2012 11:36:24) in Matlab. Is there an easy way to do this in Matlab, or am I better off using an external library (e.g. java.text.SimpleDateFormat)?
推荐答案
怎么样
date = datestr(unix_time/86400 + datenum(1970,1,1))
如果 unix_time
以秒为单位给出,unix_time/86400
将给出自 1970 年 1 月 1 日以来的天数.加上 Matlab 的 使用的偏移量datenum
(datenum(0000,1,1) == 1
),并且您拥有自 0000 年 1 月 1 日以来的天数.这可以轻松转换为人类可读的形式通过 Matlab 的 datestr
.
if unix_time
is given in seconds, unix_time/86400
will give the number of days since Jan. 1st 1970. Add to that the offset used by Matlab's datenum
(datenum(0000,1,1) == 1
), and you have the amount of days since Jan. 1st, 0000. This can be easily converted to human-readable form by Matlab's datestr
.
如果你有毫秒,就用
date = datestr(unix_time/86400/1000 + datenum(1970,1,1))
封装在函数中,这些将是
Wrapped in functions, these would be
function dn = unixtime_to_datenum( unix_time )
dn = unix_time/86400 + 719529; %# == datenum(1970,1,1)
end
function dn = unixtime_in_ms_to_datenum( unix_time_ms )
dn = unix_time_ms/86400000 + 719529; %# == datenum(1970,1,1)
end
datestr( unixtime_to_datenum( unix_time ) )
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