循环直到特定的用户输入 [英] Loop until a specific user input

问题描述

我正在尝试编写一个猜数程序，如下所示:

I am trying to write a number guessing program as follows:

def oracle():
    n = ' '
    print 'Start number = 50'
    guess = 50 #Sets 50 as a starting number
    n = raw_input("

True, False or Correct?: ")
    while True:
        if n == 'True':
            guess = guess + int(guess/5)
            print
            print 'What about',guess, '?'
            break
        elif n == 'False':
            guess = guess - int(guess/5)
            print
            print 'What about',guess, '?'
            break
        elif n == 'Correct':
            print 'Success!, your number is approximately equal to:', guess

oracle()

我现在要做的是让这一系列 if/elif/else 命令循环直到用户输入正确"，即当程序规定的数字大约等于用户数字时，但是如果我不知道用户数量，我想不出如何实现和 if 语句，而且我尝试使用while"也不起作用.

What I am trying to do now is get this sequence of if/ elif/ else commands to loop until the user enters 'Correct', i.e. when the number stated by the program is approximately equal to the users number, however if I do not know the users number I cannot think how I could implement and if statement, and my attempts to use 'while' also do not work.

推荐答案

作为@Mark Byers 方法的替代方案，您可以使用 while True:

As an alternative to @Mark Byers' approach, you can use while True:

guess = 50     # this should be outside the loop, I think
while True:    # infinite loop
    n = raw_input("

True, False or Correct?: ")
    if n == "Correct":
        break  # stops the loop
    elif n == "True":
        # etc.

这篇关于循环直到特定的用户输入的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！