直到用户输入等于做的东西 [英] Until user input equals something do

问题描述

所以，有人向我展示了如何使用条件（S）来测试，如果用户输入了输入密码。
我想坐他们的榜样了一步，使用循环（至少我是这么认为它是调用）。

So somebody showed me how to use condition(s) to test if a user had typed input for a password. I wanna take a their example a step further and use a loop (at least thats what I think it's call).

下面是他们的例子：

read -s -p "Enter new password: " NEWPASS

if test "$NEWPASS" = ""; then
    echo "Password CAN NOT be blank re-run sshd_config"
    exit 1;
fi

不是退出，我希望它继续要求输入脚本，直到有一些。

Instead of exiting the script I want it to keep asking for the input until there is some.

我要让这样的说法，但我做错了：
（现在使用顶部的例子）

I wanna make a statement like this but I was doing it wrong: (Now using top example)

该用户有机会输入新的密码，并填写变量值。

The user is given a chance to enter new password and fill the variable value.

read -s -p "Enter new password:" NEWPASS
echo ""

接下来部检查变量，看看它是否包含一个值，而值为空它要求用户无限制地填补的值。 （一环）

The next portion checks the variable to see if it contains a value, while the value is null it request the user to fill the value indefinitely. ( a loop)

while [[ -z "$NEWPASS" ]]; do
echo ""
echo "Password CAN NOT be blank"
echo ""
read -s -p "Enter new password:" NEWPASS;
echo ""
done

这行搜索含有一组由另一个文件使用的变量的文件。然后查找该文件包含PASS =行。*（*意味着什么）然后写入PASS = $ NEWPASS（$ NEWPASS是可变的）

This line searches a file containing a set of variables used by another file. It then searches the file for a line containing PASS=.* (.* meaning anything) then writes PASS=$NEWPASS ($NEWPASS being variable)

sed -i -e"s/^PASS=.*/PASS=$NEWPASS/" /etc/sshd.conf   

感谢您的所有帮助，我会用这个，并从中吸取教训。

Thank you for all the help, I'm going to use this and learn from it.

推荐答案

这while循环应该工作：

This while loop should work:

while [[ -z "$NEWPASS" ]]
do
  read -s -p "Enter new password: " NEWPASS
done

这篇关于直到用户输入等于做的东西的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！