直到用户输入匹配变量 do [英] Until user input matches variable do

问题描述

好的，所以我正在尝试创建一个用户名/密码登录脚本.(可能不是我仍在研究的最安全的想法)；)

Okay, so I'm trying to create a username/password login script of sorts. (may not be the most secure idea I'm still working on it) ;)

我的脚本将加载变量以与来自这样的文件进行比较.(现在我只是在处理密码部分)

My script will load variables to compare to from file like this. (right now I'm just working on password portion)

./path/to/variables.conf

此文件将包含一个名为

This file will contain a variable called

PASS=SOME_VALUE 

我打算用read来获取要比较的变量

I plan to use read to obtain the variable that will be compared

read -p "Enter your password:" CPASS; 

现在我缺少的部分(我设想它是如何工作的)

Now the part I'm missing (how I envision it working)

while "$CPASS" doesn't match "$PASS" do 
read -p "Wrong password, try again:" CPASS;

谢谢你&任何帮助表示赞赏.

Thank you & any help is appreciated.

推荐答案

这个应该可以.您只需要 [ ] 大括号和 != 运算符即可 比较 bash 中的字符串:

This should do it. You just need [ ] braces and the != operator to compare strings in bash:

PASS=SOME_VALUE

read -p "Enter your password:" CPASS

while [ "$CPASS" != "$PASS" ]; do 
    read -p "Wrong password, try again:" CPASS
done

还请注意，强烈建议将 -s 参数传递给读取，这样输入的密码就不会回显给用户.从 man bash 的 read 部分:

Also note it would be highly advisable to pass the -s parameter to read, so that the entered password is not echoed back to the user. From the read section of man bash:

          -s     Silent  mode.  If input is coming from a terminal, char-
                 acters are not echoed.

请注意，当用户按 ENTER 时，也不会有换行符回显给用户，因此您必须在每次 read 之后手动插入换行符，以便正确格式化行.因此，您可能应该将您的 read 语句替换为以下内容:

Note though that there will also be no newline echoed back to the user when the user hits ENTER, so you'll have to manually insert a newline after every read so that lines are properly formatted. So you should probably replace your read statements with something like this:

read -s -p "Enter your password:" CPASS
echo

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