除非用户的输入变量来匹配 [英] Until user input matches variable do

问题描述

好吧，所以我试图建立某种形式的用户名/密码登录脚本。 （未必是最安全的想法，我仍然工作就可以了）;）

Okay, so I'm trying to create a username/password login script of sorts. (may not be the most secure idea I'm still working on it) ;)

我的脚本将加载变量从这样的文件进行比较。 （现在我只是工作的一部分密码）

My script will load variables to compare to from file like this. (right now I'm just working on password portion)

./path/to/variables.conf

这个文件将包含一个名为变量

This file will contain a variable called

PASS=SOME_VALUE 

我打算使用读来获取将被比较的变量

I plan to use read to obtain the variable that will be compared

read -p "Enter your password:" CPASS; 

现在我缺少部分（我是如何设想它的工作）

Now the part I'm missing (how I envision it working)

while "$CPASS" doesn't match "$PASS" do 
read -p "Wrong password, try again:" CPASS;

感谢您和放大器;任何帮助是AP preciated。

Thank you & any help is appreciated.

推荐答案

这应该这样做。你只需要 [] 括号和 = 运营商的比较在bash 字符串：

This should do it. You just need [ ] braces and the != operator to compare strings in bash:

PASS=SOME_VALUE

read -p "Enter your password:" CPASS

while [ "$CPASS" != "$PASS" ]; do 
    read -p "Wrong password, try again:" CPASS
done

另外请注意这将是非常可取的传递 -s 参数来读取，从而使输入的密码不回显给用户。从男人庆典的读部分：

Also note it would be highly advisable to pass the -s parameter to read, so that the entered password is not echoed back to the user. From the read section of man bash:

          -s     Silent  mode.  If input is coming from a terminal, char-
                 acters are not echoed.

请注意，虽然有也不会换行回显到用户，当用户点击回车，所以你必须手动插入后，每一个新行读等等该行格式正确。所以，你应该像这样替换你读的语句：

Note though that there will also be no newline echoed back to the user when the user hits ENTER, so you'll have to manually insert a newline after every read so that lines are properly formatted. So you should probably replace your read statements with something like this:

read -s -p "Enter your password:" CPASS
echo

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