有没有办法将函数存储在列表或字典中,以便在调用索引(或键)时触发存储的函数? [英] Is there a way to store a function in a list or dictionary so that when the index (or key) is called it fires off the stored function?
问题描述
例如,我尝试过类似 mydict = {'funcList1': [foo(),bar(),goo()], 'funcList2': [foo(),goo(),bar()]
,这不起作用.
For instance, I've tried things like mydict = {'funcList1': [foo(),bar(),goo()], 'funcList2': [foo(),goo(),bar()]
, which doesn't work.
是否有某种结构具有这种功能?
Is there some kind of structure with this kind of functionality?
我意识到我显然可以用一堆 def
语句轻松地做到这一点:
I realize that I could obviously do this just as easily with a bunch of def
statements:
def func1():
foo()
bar()
goo()
但是我需要的语句数量变得非常笨拙且难以记住.将它们很好地包装在字典中会很好,我可以一次又一次地检查键.
But the number of statements I need is getting pretty unwieldy and tough to remember. It would be nice to wrap them nicely in a dictionary that I could examine the keys of now and again.
推荐答案
函数是 Python 中的第一类对象,因此您可以使用字典进行调度.例如,如果 foo
和 bar
是函数,而 dispatcher
是这样的字典.
Functions are first class objects in Python and so you can dispatch using a dictionary. For example, if foo
and bar
are functions, and dispatcher
is a dictionary like so.
dispatcher = {'foo': foo, 'bar': bar}
注意,值是 foo
和 bar
,它们是函数对象,而不是 foo()
和 bar()
.
Note that the values are foo
and bar
which are the function objects, and NOT foo()
and bar()
.
要调用foo
,只需执行dispatcher['foo']()
如果您想运行存储在列表中的多个函数,您可以这样做.
If you want to run multiple functions stored in a list, you can possibly do something like this.
dispatcher = {'foobar': [foo, bar], 'bazcat': [baz, cat]}
def fire_all(func_list):
for f in func_list:
f()
fire_all(dispatcher['foobar'])
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