如何解决 php json_decode 中的 JSON_ERROR_UTF8 错误? [英] How to solve JSON_ERROR_UTF8 error in php json_decode?

问题描述

我正在尝试这个代码

$json = file_get_contents("http://www.google.com/alerts/preview?q=test&t=7&f=1&l=0&e");
print_r(json_decode(utf8_encode($json), true));

        //////////////

// Define the errors.
$constants = get_defined_constants(true);
$json_errors = array();
foreach ($constants["json"] as $name => $value) {
    if (!strncmp($name, "JSON_ERROR_", 11)) {
        $json_errors[$value] = $name;
    }
}

// Show the errors for different depths.
foreach (range(4, 3, -1) as $depth) {
    var_dump(json_decode($json, true, $depth));
    echo 'Last error: ', $json_errors[json_last_error()], PHP_EOL, PHP_EOL;
}

我尝试了很多函数，html_entities_decode、utf8_encode 和 decode，解码十六进制代码，但我总是收到错误JSON_ERROR_UTF8".

I've tried a lot of functions, html_entities_decode, utf8_encode and decode, decoding the hex codes, but I always get the error "JSON_ERROR_UTF8".

我该如何解决这个问题?

推荐答案

有一个很好的函数 来清理你的数组.

我建议你使用这样的 json_encode 包装器:

I suggest you use a json_encode wrapper like this :

function safe_json_encode($value, $options = 0, $depth = 512, $utfErrorFlag = false) {
    $encoded = json_encode($value, $options, $depth);
    switch (json_last_error()) {
        case JSON_ERROR_NONE:
            return $encoded;
        case JSON_ERROR_DEPTH:
            return 'Maximum stack depth exceeded'; // or trigger_error() or throw new Exception()
        case JSON_ERROR_STATE_MISMATCH:
            return 'Underflow or the modes mismatch'; // or trigger_error() or throw new Exception()
        case JSON_ERROR_CTRL_CHAR:
            return 'Unexpected control character found';
        case JSON_ERROR_SYNTAX:
            return 'Syntax error, malformed JSON'; // or trigger_error() or throw new Exception()
        case JSON_ERROR_UTF8:
            $clean = utf8ize($value);
            if ($utfErrorFlag) {
                return 'UTF8 encoding error'; // or trigger_error() or throw new Exception()
            }
            return safe_json_encode($clean, $options, $depth, true);
        default:
            return 'Unknown error'; // or trigger_error() or throw new Exception()

    }
}

function utf8ize($mixed) {
    if (is_array($mixed)) {
        foreach ($mixed as $key => $value) {
            $mixed[$key] = utf8ize($value);
        }
    } else if (is_string ($mixed)) {
        return utf8_encode($mixed);
    }
    return $mixed;
}

在我的应用程序中 utf8_encode() 比 iconv() 效果更好

In my application utf8_encode() works better than iconv()

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