我如何映射“根"?Servlet 以便其他脚本仍然可以运行? [英] How can I map a "root" Servlet so that other scripts are still runnable?

问题描述

我正在尝试构建一个调用类似于以下 JSP 页面的 Servlet:

I'm trying to build a Servlet that calls a JSP page similar to the following:

public void doGet(HttpServletRequest req, HttpServletResponse resp)
        throws IOException, ServletException {
    req.getRequestDispatcher("/WEB-INF/main.jsp").forward(req, resp);
}

我需要这个 Servlet 来响应域的根(例如:http://example.com/)所以我在 web.xml 中使用以下映射:

I need this Servlet to respond to the domain's root (eg: http://example.com/) so I'm using the following mapping in the web.xml:

<servlet-mapping>
    <servlet-name>MainServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

我遇到的问题是它匹配所有内容，因此当调度程序转发到/WEB-INF/main.jsp"时，它匹配 url-pattern，因此 Servlet 再次运行.这会导致循环运行，直到它以 java.lang.StackOverflowError.

The problem I'm having is that this matches EVERYTHING, so when the dispatcher forwards to "/WEB-INF/main.jsp" this matches the url-pattern so the Servlet gets run again. This results in a loop that runs until it dies with a java.lang.StackOverflowError.

如何在不阻止其他脚本运行的情况下匹配根?

How can I match the root without preventing other scripts from being runnable?

推荐答案

使用空模式，例如

<servlet-mapping>
    <servlet-name>MainServlet</servlet-name>
    <url-pattern></url-pattern>
</servlet-mapping>

servlet 3.0 规范对此进行了澄清:

The servlet 3.0 spec has clarified this:

空字符串 ("") 是一种特殊的 URL 模式，它精确地映射到应用程序的上下文根

The empty string ("") is a special URL pattern that exactly maps to the application's context root

所以它至少应该在 3.0 容器上工作，我已经验证它在 Jetty 8 上工作

So it should at least work on a 3.0 container, and I've verified that it works on Jetty 8

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