如何从两个位置的经纬度找到距离? [英] How to find distance from the latitude and longitude of two locations?

问题描述

我有一组位置的纬度和经度.

I have a set of latitudes and longitudes of locations.

• 如何找到从集合中的一个位置到另一个位置的距离?
• 有公式吗?

推荐答案

Haversine 公式假设地球是球形的.然而，耳朵的形状更为复杂.扁球体模型会得到更好的结果.

The Haversine formula assumes a spherical earth. However, the shape of the earh is more complex. An oblate spheroid model will give better results.

如果需要这样的精度，最好使用Vincenty 逆公式.有关详细信息，请参阅 http://en.wikipedia.org/wiki/Vincenty's_formulae.使用它，您可以获得 0.5mm 的球体模型精度.

If such accuracy is needed, you should better use Vincenty inverse formula. See http://en.wikipedia.org/wiki/Vincenty's_formulae for details. Using it, you can get a 0.5mm accuracy for the spheroid model.

没有完美的公式，因为地球的真实形状太复杂，无法用公式表达.此外，地球的形状会因气候事件而发生变化(参见 http://www.nasa.gov/centers/goddard/earthandsun/earthshape.html)，也会随着地球自转而随时间变化.

There is no perfect formula, since the real shape of the earth is too complex to be expressed by a formula. Moreover, the shape of earth changes due to climate events (see http://www.nasa.gov/centers/goddard/earthandsun/earthshape.html), and also changes over time due to the rotation of the earth.

您还应该注意，上述方法没有考虑高度，并且假设是海平面扁球体.

You should also note that the method above does not take altitudes into account, and assumes a sea-level oblate spheroid.

2010 年 7 月 10 日编辑:我发现在极少数情况下 Vincenty 逆公式不会收敛到声明的准确度.一个更好的主意是使用 GeographicLib(参见 http://sourceforge.net/projects/geographiclib/)这也更准确.

Edit 10-Jul-2010: I found out that there are rare situations for which Vincenty inverse formula does not converge to the declared accuracy. A better idea is to use GeographicLib (see http://sourceforge.net/projects/geographiclib/) which is also more accurate.

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