如何找到从两个位置的纬度和经度距离是多少？ [英] How to find distance from the latitude and longitude of two locations?
问题描述
我有一组纬度和经度位置的。
I have a set of latitudes and longitudes of locations.
- 如何找到的设置为另一个距离从一个位置？
- 有没有公式？
- How to find distance from one location in the set to another?
- Is there a formula ?
推荐答案
在半正矢公式假设一个球形的地球。然而，earh的形状更复杂。一个扁球体模型会给出更好的结果。
The Haversine formula assumes a spherical earth. However, the shape of the earh is more complex. An oblate spheroid model will give better results.
如果这样的精度是必要的，你最好使用 Vincenty反式。 请参阅<一href="http://en.wikipedia.org/wiki/Vincenty%27s_formulae">http://en.wikipedia.org/wiki/Vincenty's_formulae了解详细信息。使用它，你可以得到0.5mm的精度球体模型。
If such accuracy is needed, you should better use Vincenty inverse formula. See http://en.wikipedia.org/wiki/Vincenty's_formulae for details. Using it, you can get a 0.5mm accuracy for the spheroid model.
没有完美的公式，因为地球的真正形状太复杂，无法用一个公式pssed EX $ P $。此外，地球的变化，由于气候事件的形状（见<一href="http://www.nasa.gov/centers/goddard/earthandsun/earthshape.html">http://www.nasa.gov/centers/goddard/earthandsun/earthshape.html),并且也由于地球的旋转随时间改变。
There is no perfect formula, since the real shape of the earth is too complex to be expressed by a formula. Moreover, the shape of earth changes due to climate events (see http://www.nasa.gov/centers/goddard/earthandsun/earthshape.html), and also changes over time due to the rotation of the earth.
您还应该注意的是，上述方法没有考虑高度考虑，并假定海平面的扁球体。
You should also note that the method above does not take altitudes into account, and assumes a sea-level oblate spheroid.
修改10 07月2010：我发现有极少数情况下为其Vincenty反式不收敛于声明的准确性。更好的方法是使用GeographicLib（见<一href="http://sourceforge.net/projects/geographiclib/">http://sourceforge.net/projects/geographiclib/)这也是更准确。
Edit 10-Jul-2010: I found out that there are rare situations for which Vincenty inverse formula does not converge to the declared accuracy. A better idea is to use GeographicLib (see http://sourceforge.net/projects/geographiclib/) which is also more accurate.
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