在 GCC/G++ 编译器中使用 -pedantic 的目的是什么? [英] What is the purpose of using -pedantic in the GCC/G++ compiler?

问题描述

这篇笔记说:

-ansi:告诉编译器实现ANSI语言选项.这转关闭某些功能"海湾合作委员会的与 ANSI 不兼容标准.

-ansi: tells the compiler to implement the ANSI language option. This turns off certain "features" of GCC which are incompatible with the ANSI standard.

-pedantic:与-ansi结合使用，告诉编译器严格遵守ANSI标准，拒绝任何不是的代码合规.

-pedantic: used in conjunction with -ansi, this tells the compiler to be adhere strictly to the ANSI standard, rejecting any code which is not compliant.

第一件事:

• GCC/G++ 编译器的 -pedantic 和 -ansi 选项的目的是什么(我无法理解上面的描述)?
• 使用这两个选项的正确情况是什么?
• 我应该什么时候使用它们?
• 它们重要吗?

• What is the purpose of the -pedantic and -ansi options of the GCC/G++ compiler (I couldn't understand the above description)?
• What are the right circumstances for using these two options?
• When should I use them?
• Are they important?

推荐答案

如果可能的话，GCC 编译器总是会尝试编译您的程序.然而，在一些在这种情况下，C 和 C++ 标准规定禁止某些扩展.符合标准的编译器遇到这些扩展时，例如 GCC 或 g++ 必须发出诊断信息.

GCC compilers always try to compile your program if this is at all possible. However, in some cases, the C and C++ standards specify that certain extensions are forbidden. Conforming compilers such as GCC or g++ must issue a diagnostic when these extensions are encountered.

例如，GCC 编译器的-pedantic 选项会导致 GCC 在这种情况下发出警告.使用更严格的-pedantic-errors 选项将此类诊断警告转换为将导致编译在此类点失败的错误.只有那些需要由符合标准的编译器标记的非 ISO 构造才会生成警告或错误.

For example, the GCC compiler’s -pedantic option causes GCC to issue warnings in such cases. Using the stricter -pedantic-errors option converts such diagnostic warnings into errors that will cause compilation to fail at such points. Only those non-ISO constructs that are required to be flagged by a conforming compiler will generate warnings or errors.

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