JSON 序列化类继承列表上的属性 [英] JSON serialize properties on class inheriting list

问题描述

我有一个模型如下:

公共类TestResultModel{公共布尔成功{得到;放;}公共字符串 ErrorMessage { 获取；放;}}公共类 TestResultListModel : List{public int TotalTestCases { get { return base.Count;} }public int TotalSuccessful { get { return base.FindAll(t => t.Successful).Count;} }}

我从 ApiController 返回这个 TestResultListModel:

var testResultListModel = new TestResultListModel();foreach (var testCaseId in new int[] {1,2,3,4}){var testResultModel = 新的 TestResultModel{成功=真，错误消息 = "STRING"};testResultListModel.Add(testResultModel);}返回 testResultListModel;

当我检查 JSON 结果时，它确实包含所有 TestResultModel，但是 TestResultListModel 上的属性(TotalTestCases 和 TotalSuccesful) 不可见.

如何将这些值也包含在 JSON 序列化对象中?

我尝试的是使用 JSON.NET 并使用属性 [JsonProperty] 装饰属性，但没有成功.

解决方案

这里的基本困难是 JSON 有两种类型的容器:对象和数组.来自标准:

• 数组是值的有序集合.数组以[(左括号)开始，以](右括号)结束.值由 , (逗号)分隔.

• 对象是一组无序的名称/值对.一个对象以{(左大括号)开始，以}(右大括号)结束.

要强制序列化集合的属性，请使用 [JsonObject]:

[JsonObject]公共类 TestResultListModel : List{public int TotalTestCases { get { return base.Count;} }public int TotalSuccessful { get { return base.FindAll(t => t.Successful).Count;} }}

当然，如果您这样做，项目将不会被序列化，因为 JSON 容器可以拥有属性或项目——但不能同时拥有.如果两者都需要，则需要添加一个合成数组属性来保存项目——如果需要，它可以是私有的.

[JsonObject] 也会导致诸如 Capacity 被序列化，你可能不想要.要取消基类属性，请使用 MemberSerialization.OptIn.因此，您的最终课程应该类似于:

[JsonObject(MemberSerialization = MemberSerialization.OptIn)]公共类 TestResultListModel : List{[Json属性]public int TotalTestCases { get { return base.Count;} }[Json属性]//使用 Enumerable.Count() 比 List.FindAll() 更节省内存public int TotalSuccessful { get { return this.Count(t => t.Successful);} }[Json属性]TestResultModel[] 项目{得到{返回 this.ToArray();}放{如果(值！= null)this.AddRange(value);}}}

这给出了如下所示的 JSON:

<块引用>

<代码>{"TotalTestCases": 4,总成功":2，项目": [{成功":假，错误消息":字符串"},{成功":真的，错误消息":字符串"},{成功":假，错误消息":字符串"},{成功":真的，错误消息":字符串"}]}

这可能比它的价值更多的工作，因为这些属性可以在客户端轻松重建.(问题为什么不从 List 继承? 建议避免这种设计.)

I have a model as follows:

public class TestResultModel
{
    public bool Successful { get; set; }
    public string ErrorMessage { get; set; }
}

public class TestResultListModel : List<TestResultModel>
{
    public int TotalTestCases { get { return base.Count; } }

    public int TotalSuccessful { get { return base.FindAll(t => t.Successful).Count; } }
}

I return this TestResultListModel from an ApiController:

var testResultListModel = new TestResultListModel();
foreach (var testCaseId in new int[] {1,2,3,4})
{
    var testResultModel = new TestResultModel
    {
        Successful = true,
        ErrorMessage = "STRING"
    };

    testResultListModel.Add(testResultModel);
}
return testResultListModel;

When I inspect the JSON result it does contain all the TestResultModels, but the properties on the TestResultListModel (TotalTestCases and TotalSuccesful) are not visible.

How can I also include these values in the JSON-serialized object?

What I tried is using JSON.NET and decorating the properties with the attribute [JsonProperty], this was unsuccessful.

解决方案

Your basic difficulty here is that JSON has two types of container: an object, and an array. From the standard:

• An array is an ordered collection of values. An array begins with [ (left bracket) and ends with ] (right bracket). Values are separated by , (comma).

• An object is an unordered set of name/value pairs. An object begins with { (left brace) and ends with } (right brace).

To force a collection's properties to be serialized, mark it with [JsonObject]:

[JsonObject]
public class TestResultListModel : List<TestResultModel>
{
    public int TotalTestCases { get { return base.Count; } }

    public int TotalSuccessful { get { return base.FindAll(t => t.Successful).Count; } }
}

Of course, if you do this, the items will not be serialized, because a JSON container can have properties, or items -- but not both. If you want both, you will need to add a synthetic array property to hold the items -- which can be private if you want.

[JsonObject] will also cause base class properties such as Capacity to be serialized, which you likely do not want. To suppress base class properties, use MemberSerialization.OptIn. Thus your final class should look something like:

[JsonObject(MemberSerialization = MemberSerialization.OptIn)]
public class TestResultListModel : List<TestResultModel>
{
    [JsonProperty]
    public int TotalTestCases { get { return base.Count; } }

    [JsonProperty]
    // Using Enumerable.Count() is more memory efficient than List.FindAll()
    public int TotalSuccessful { get { return this.Count(t => t.Successful); } }

    [JsonProperty]
    TestResultModel[] Items
    {
        get
        {
            return this.ToArray();
        }
        set
        {
            if (value != null)
                this.AddRange(value);
        }
    }
}

This gives JSON that looks like:

{
  "TotalTestCases": 4,
  "TotalSuccessful": 2,
  "Items": [
    {
      "Successful": false,
      "ErrorMessage": "STRING"
    },
    {
      "Successful": true,
      "ErrorMessage": "STRING"
    },
    {
      "Successful": false,
      "ErrorMessage": "STRING"
    },
    {
      "Successful": true,
      "ErrorMessage": "STRING"
    }
  ]
}

It is possibly more work than it's worth, since these properties could be reconstructed easily on the client side. (The question Why not inherit from List? suggests avoiding this sort of design.)

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