std::vector 删除满足某些条件的元素 [英] std::vector removing elements which fulfill some conditions

问题描述

正如标题所说，我想删除/合并满足特定条件的向量中的对象.我的意思是我知道如何从向量中删除整数，例如，其值为 99.

As the title says I want to remove/merge objects in a vector which fulfill specific conditions. I mean I know how to remove integers from a vector which have the value 99 for instance.

Scott Meyers 的 remove 成语:

The remove idiom by Scott Meyers:

vector<int> v;
v.erase(remove(v.begin(), v.end(), 99), v.end());

但是假设是否有一个包含延迟成员变量的对象向量.现在我想消除所有延迟差异仅小于特定阈值的对象，并希望将它们组合/合并为一个对象.

But suppose if have a vector of objects which contains a delay member variable. And now I want to eliminate all objects which delays differs only less than a specific threshold and want to combine/merge them to one object.

过程的结果应该是一个对象向量，其中所有延迟的差异至少应该是指定的阈值.

The result of the process should be a vector of objects where the difference of all delays should be at least the specified threshold.

推荐答案

std::remove_if来拯救！

99 将被替换为 UnaryPredicate，它会过滤您的延迟，我将使用 lambda 函数来实现.

99 would be replaced by UnaryPredicate that would filter your delays, which I am going to use a lambda function for.

这是一个例子:

v.erase(std::remove_if(
    v.begin(), v.end(),
    [](const int& x) { 
        return x > 10; // put your condition here
    }), v.end());

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