在 bash 脚本中提取 XML 值 [英] Extract XML Value in bash script

问题描述

我正在尝试从已作为变量读入我的脚本的 xml 文档中提取一个值.原始变量 $data 是:

I'm trying to extract a value from an xml document that has been read into my script as a variable. The original variable, $data, is:

<item> 
  <title>15:54:57 - George:</title>
  <description>Diane DeConn? You saw Diane DeConn!</description> 
</item> 
<item> 
  <title>15:55:17 - Jerry:</title> 
  <description>Something huh?</description>
</item> 

我想提取第一个标题值，所以

and I wish to extract the first title value, so

15:54:57 - George:

我一直在使用 sed 命令:

I've been using the sed command:

title=$(sed -n -e 's/.*<title>(.*)</title>.*/1/p' <<< $data)

但这只会输出第二个标题值:

but this only outputs the second title value:

15:55:17 - Jerry:

有谁知道我做错了什么?谢谢！

Does anyone know what I have done wrong? Thanks!

推荐答案

正如 Charles Duffey 所说，XML 解析器是最好使用适当的 XML 解析工具进行解析.对于一次工作，以下应该有效.

As Charles Duffey has stated, XML parsers are best parsed with a proper XML parsing tools. For one time job the following should work.

grep -oPm1 "(?<=<title>)[^<]+"

测试:

$ echo "$data"
<item> 
  <title>15:54:57 - George:</title>
  <description>Diane DeConn? You saw Diane DeConn!</description> 
</item> 
<item> 
  <title>15:55:17 - Jerry:</title> 
  <description>Something huh?</description>
$ title=$(grep -oPm1 "(?<=<title>)[^<]+" <<< "$data")
$ echo "$title"
15:54:57 - George:

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