在bash脚本中提取JSON值的更好方法 [英] A better way to extract JSON value in bash script

问题描述

有人能建议我从Json对中提取值的更好/更巧妙的方法吗?

Can anyone suggest a better / neater way to extract the value from a Json pair than what I've got so far below pls...

我的Json对是

{"myKeyName":"myKeyValueVariableLength"}

存储在myFile.txt中，我只想要KeyValue(不带引号).我目前所拥有的是:

is stored in myFile.txt and I just want the KeyValue (without quotes). What I've currently got is :

#!/bin/bash
PAIR=$(<myFile.txt)
IFS=': ' read -a arr <<< $PAIR
ONE="${arr[1]%?}"
TWO="${ONE%?}"
THREE=${TWO#'"'}
echo $THREE

这确实对我有用，但是我猜有更整齐的方法了吗?我听说过jsawk，但想尝试并尽可能在bash中做所有事情.

This does work for me but I'm guessing there is a much neater way ? I have heard of jsawk but would like to try and do all within bash if possible.

Tks

推荐答案

Bash包含一个内置的正则表达式测试，格式为[[ string =~ regex ]].运行后，捕获的子模式将存储在名为$BASH_REMATCH

Bash contains a built-in regex test, which takes the form [[ string =~ regex ]]. After it's run, captured sub-patterns are stored in an array called $BASH_REMATCH

在处理引号和转义时有点麻烦/不可思议，所以我花了一些时间才能开始工作，但这似乎行得通:

It's a bit fussy / magic about handling quotes and escapes, so it took me a while to get working, but this seems to work:

PAIR='{"myKeyName":"myKeyValueVariableLength"}'
[[ $PAIR =~ ^\{\"([^\"]+)\":\"([^\"]+)\"\}$ ]] && echo "The key is ${BASH_REMATCH[1]} and the value is ${BASH_REMATCH[2]}"

[或者，以Unix方式执行，然后调用sed，awk，perl，python，php或已安装的任何可简化生活的方法.类似于php -r "print_r( json_decode('"$PAIR"') );"的内容...]

[Alternatively, do it The Unix Way, and invoke sed, awk, perl, python, php, or whatever you have installed that will make your life easier. Something along the lines of php -r "print_r( json_decode('"$PAIR"') );" for instance...]

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