无法在 jQuery Datatable 中列出详细信息数据 [英] Cannot list details data in jQuery Datatable

问题描述

我遵循了 jQuery 数据表 - 滑动子行 示例(只需查看完整代码" 部分)在我的 ASP.NET MVC 项目中，我可以列出 master &静态细节数据正确.但是，当我想通过 AJAX 动态检索详细信息数据时，由于错误 TypeError: table.fnOpen is not a function，我无法正确列出它们.有一个将 DataTable 更改为 dataTable 的解决方案，但在这种情况下，我遇到了另一个错误.问题正是在点击 &format 方法，我想我在某些定义上犯了一个错误.你能看一下并澄清错误在哪里吗?提前致谢...

I followed jQuery Datatable - Sliding child rows example (just look at "Complete code" section on that page) in my ASP.NET MVC project and I could listed master & static details data properly. However, when I want to retrieve details data dynamically via AJAX, I cannot listed them properly due to an error TypeError: table.fnOpen is not a function. There is a solution changing DataTable to dataTable, but in this case I encounter another errors. The problem is exactly on the click & format method and I think I made a mistake for some definition. Could you please have a look at and clarify me about where the mistake is? Thanks in advance...

function format(d) {
    return '<div class="slider">' +
    '<table style="width:100%">' +
      '<tr>' +
            '<th>Name</th>' +
            '<th>Surname</th> ' +
            '<th>Number</th>' +
        '</tr>' +
        '<tr>' +
            '<td>' + d.StudentName + '</td>' +
            '<td>' + d.StudentSurname + '</td> ' +
            '<td>' + d.StudentNumber + '</td>' +
        '</tr>' +
    '</table>'
    '</div>';
}


$(document).ready(function () {

    var table;
    table = $('#dtbLabGroup')
        .DataTable(

        //code omitted for brevity

        "columns": [
                    {
                        "class": 'details-control',
                        "orderable": false,
                        "data": null,
                        "defaultContent": ''
                    },
                    { "name": "Lab" },
                    { "name": "Schedule" },
                    { "name": "Term" },
                    { "name": "Status" }
        ],          
        "order": [[1, 'asc']],
    });


    // Add event listener for opening and closing details
    $('#dtbLabGroup tbody').on('click', 'td.details-control', function () {

        // !!! There might be a problem regarding to these 3 parameters
        var tr = $(this).closest('tr');
        var row = table.row(tr);            
        var nTr = $(this).parents('tr')[0];
        //

        if (row.child.isShown()) {
            // This row is already open - close it
            $('div.slider', row.child()).slideUp(function () {
                row.child.hide();
                tr.removeClass('shown');
            });
        }
        else {
            // Open this row
            row.child(format(row.data()), 'no-padding').show();
            tr.addClass('shown');

            $('div.slider', row.child()).slideDown();

            // !!! There is PROBABLY a problem
            // !!! I added the following code for retrieving data via AJAX call. 
            var id = 8; //used static id for testing
            $.get("GetStudents?id=" + id, function (students) {
                table.fnOpen(nTr, students, 'details');
            });
        }
    }); 

}); 

更新一:下面是修改后的 format() 方法:

Update I: Here is the modified format() method below:

function format(d) {
    var htmlResult = '<div class="slider">' +
    '<table style="width:100%">' +
      '<tr>' +
            '<th>Name</th>' +
            '<th>Surname</th> ' +
            '<th>Number</th>' +
        '</tr>';

       $.each(d, function (i, d) {
           htmlResult += '<tr><td>' + d[i].StudentName + '</td><td>' + d[i].StudentSurname + '</td><td>' + d[i].StudentNumber + '</td></tr>';
       });

    htmlResult += '</table>' +
    '</div>';
    return htmlResult;
}

推荐答案

您需要在子行显示加载指示器，通过 Ajax 检索内容并将其注入子行替换加载指示器.

You need to show loading indicator in the child row, retrieve content via Ajax and inject it into the child row replacing loading indicator.

例如:

// ... skipped ...

// Open this row
row.child('<p><center>Loading...</center></p>', 'no-padding' ).show();
tr.addClass('shown');
$('div.slider', row.child()).slideDown();

$.getJSON("GetStudents?id=" + id, function(data){
   $('td', row.child()).html(format(data));
   $('div.slider', row.child()).show();
});

// ... skipped ...

有关代码和演示，请参阅此示例.

See this example for code and demonstration.

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