如何在 Swift 中删除视图的所有子视图? [英] How to remove all subviews of a view in Swift?

问题描述

我正在寻找一种简单的方法来一次从超级视图中删除所有子视图，而不是一个一个地删除它们.

I'm looking for a simple method to remove at once all subviews from a superview instead of removing them one by one.

//I'm trying something like this, but is not working
let theSubviews : Array = container_view.subviews
for (view : NSView) in theSubviews {
    view.removeFromSuperview(container_view)
}

我缺少什么?

更新

我的应用有一个主要的container_view.我必须将不同的其他视图作为子视图添加到 container_view 以提供一种导航.

My app has a main container_view. I have to add different other views as subviews to container_view in order to provide a sort of navigation.

因此，当单击按钮打开"特定页面时，我需要删除所有子视图并添加新的.

So, when clicking the button to "open" a particular page, I need to remove allsubviews and add the new one.

更新 2 - 一个可行的解决方案 (OS X)

我猜苹果修复了它.

现在比以往任何时候都容易，只需调用:

Now it is more easy than ever, just call:

for view in containerView.subviews{
    view.removeFromSuperview()
}

推荐答案

(感谢 Jeremiah/Rollo)

(thanks Jeremiah / Rollo)

到目前为止，在 iOS 版 Swift 中执行此操作的最佳方法是:

By far the best way to do this in Swift for iOS is:

view.subviews.forEach({ $0.removeFromSuperview() }) // this gets things done
view.subviews.map({ $0.removeFromSuperview() }) // this returns modified array

^^ 这些功能很有趣！

^^ These features are fun!

let funTimes = ["Awesome","Crazy","WTF"]
extension String { 
    func readIt() {
        print(self)
    }
}

funTimes.forEach({ $0.readIt() })

////结束编辑

就这样做:

for view in self.view.subviews {
    view.removeFromSuperview()
}

或者如果您正在寻找特定的课程

Or if you are looking for a specific class

for view:CustomViewClass! in self.view.subviews {
        if view.isKindOfClass(CustomViewClass) {
            view.doClassThing()
        }
    }

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