Python:在python中做几何平均值的简单方法? [英] Python : easy way to do geometric mean in python?

问题描述

我想知道有没有什么简单的方法可以使用 python 但不使用 python 包来做几何平均.如果没有，有没有简单的包来做几何平均?

I wonder is there any easy way to do geometric mean using python but without using python package. If there is not, is there any simple package to do geometric mean?

推荐答案

几何均值的公式为:

因此您可以轻松编写如下算法:

So you can easily write an algorithm like:

import numpy as np

def geo_mean(iterable):
    a = np.array(iterable)
    return a.prod()**(1.0/len(a))

您不必为此使用 numpy，但它在数组上执行操作的速度往往比 Python 快.请参阅此答案以了解原因.

You do not have to use numpy for that, but it tends to perform operations on arrays faster than Python. See this answer for why.

如果溢出的可能性很高，您可以先将数字映射到log域，计算这些日志的总和，然后乘以1/n最后计算指数，如:

In case the chances of overflow are high, you can map the numbers to a log domain first, calculate the sum of these logs, then multiply by 1/n and finally calculate the exponent, like:

import numpy as np

def geo_mean_overflow(iterable):
    return np.exp(np.log(iterable).mean())

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