C++ 是否支持“最终"块?(我一直听到的这个“RAII"是什么?) [英] Does C++ support 'finally' blocks? (And what's this 'RAII' I keep hearing about?)

查看:34
本文介绍了C++ 是否支持“最终"块?(我一直听到的这个“RAII"是什么?)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

C++ 是否支持'finally'块?

Does C++ support 'finally' blocks?

什么是 RAII 习语?

C++的RAII习语和C#的'有什么区别使用'语句?

What is the difference between C++'s RAII idiom and C#'s 'using' statement?

推荐答案

不,C++ 不支持finally"块.原因是 C++ 支持 RAII:Resource Acquisition Is Initialization"——一个真正有用的概念糟糕的名字.

No, C++ does not support 'finally' blocks. The reason is that C++ instead supports RAII: "Resource Acquisition Is Initialization" -- a poor name for a really useful concept.

这个想法是对象的析构函数负责释放资源.当对象具有自动存储持续时间时,对象的析构函数将在创建它的块退出时被调用——即使该块在存在异常的情况下退出.以下是 Bjarne Stroustrup 对该主题的解释.

The idea is that an object's destructor is responsible for freeing resources. When the object has automatic storage duration, the object's destructor will be called when the block in which it was created exits -- even when that block is exited in the presence of an exception. Here is Bjarne Stroustrup's explanation of the topic.

RAII 的一个常见用途是锁定互斥锁:

A common use for RAII is locking a mutex:

// A class with implements RAII
class lock
{
    mutex &m_;

public:
    lock(mutex &m)
      : m_(m)
    {
        m.acquire();
    }
    ~lock()
    {
        m_.release();
    }
};

// A class which uses 'mutex' and 'lock' objects
class foo
{
    mutex mutex_; // mutex for locking 'foo' object
public:
    void bar()
    {
        lock scopeLock(mutex_); // lock object.

        foobar(); // an operation which may throw an exception

        // scopeLock will be destructed even if an exception
        // occurs, which will release the mutex and allow
        // other functions to lock the object and run.
    }
};

RAII 还简化了将对象用作其他类的成员.当拥有类'被破坏时,由 RAII 类管理的资源被释放,因为 RAII 管理类的析构函数被调用.这意味着当您对管理资源的类中的所有成员使用 RAII 时,您可以使用非常简单的,甚至可能是默认的析构函数,因为它不需要手动管理其成员资源的生命周期..(感谢 Mike B 指出这一点.)

RAII also simplifies using objects as members of other classes. When the owning class' is destructed, the resource managed by the RAII class gets released because the destructor for the RAII-managed class gets called as a result. This means that when you use RAII for all members in a class that manage resources, you can get away with using a very simple, maybe even the default, destructor for the owner class since it doesn't need to manually manage its member resource lifetimes. (Thanks to Mike B for pointing this out.)

对于熟悉 C# 或 VB.NET 的人来说,您可能会发现 RAII 类似于 .NET 确定性销毁使用 IDisposable 和 'using' 语句.确实,这两种方法非常相似.主要区别在于 RAII 将确定性地释放任何类型的资源——包括内存.在 .NET(甚至是 .NET 语言 C++/CLI)中实现 IDisposable 时,将确定性地释放除内存之外的资源.在 .NET 中,内存不是确定性释放的;内存只在垃圾回收周期释放.

For those familliar with C# or VB.NET, you may recognize that RAII is similar to .NET deterministic destruction using IDisposable and 'using' statements. Indeed, the two methods are very similar. The main difference is that RAII will deterministically release any type of resource -- including memory. When implementing IDisposable in .NET (even the .NET language C++/CLI), resources will be deterministically released except for memory. In .NET, memory is not deterministically released; memory is only released during garbage collection cycles.

 

† 有些人认为破坏就是资源放弃"是 RAII 习语的更准确名称.

† Some people believe that "Destruction is Resource Relinquishment" is a more accurate name for the RAII idiom.

这篇关于C++ 是否支持“最终"块?(我一直听到的这个“RAII"是什么?)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆