见过这种二进制日期格式吗? [英] Seen this binary date format?

问题描述

3/10/2008 = 1822556159

3/10/2008 = 1822556159

2/10/2008 = 1822523391

2/10/2008 = 1822523391

2008 年 1 月 10 日 = 1822490623

1/10/2008 = 1822490623

30/09/2008 = 1822392319

30/09/2008 = 1822392319

29/09/2008 = 1822359551

29/09/2008 = 1822359551

这是我目前所知道的所有信息.

This is all the information that I know at the current time.

日期增量为 32768，除非更改月份时增量为 32768 x 2 (65536).

Dates increment by 32768 except when changing month when the increment is 32768 x 2 (65536).

有人见过这种二进制日期格式吗?如何提取正确的日期?

Has anyone seen this binary date format and how can I extract the correct date?

日期的剩余部分可能是时间(小时、分钟、秒)

It is possible that the remaining portion of the date is for time (hours, minutes, seconds)

推荐答案

2008 年 9 月 30 日

September 30th 2008

1822392319 = 0x6c9f7fff
0x6c = 108 = 2008 (based on 1900 start date)
0x9 = 9 = September
0xf7fff - take top 5 bits = 0x1e = 30

2008 年 10 月 1 日

October 1st 2008

1822490623 = 0x6ca0ffff
0x6c = 108 = 2008
0xa = 10  = October
0x0ffff  - take top 5 bits = 0x01 = 1

如果有的话，任何人都可以猜测剩下的 15 个 1 位是干什么用的.

It's anyone's guess what the remaining 15 one-bits are for, if anything.

我的意思是取前 5 位:

by take top 5 bits I mean:

day_of_month = (value >> 15) & 0x1f

同样:

year = (value >> 24) & 0xff + 1900
month = (value >> 20) & 0x0f

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