看到这个二进制日期格式？ [英] Seen this binary date format?

问题描述

3/10/2008 = 1822556159

3/10/2008 = 1822556159

2/10/2008 = 1822523391

2/10/2008 = 1822523391

1/10 / 2008 = 1822490623

1/10/2008 = 1822490623

30/09/2008 = 1822392319

30/09/2008 = 1822392319

29/09/2008 = 1822359551

29/09/2008 = 1822359551

这是我当前知道的所有信息。

This is all the information that I know at the current time.

日期增加32768，除了当增量为32768 x 2（65536）更改月份时。

Dates increment by 32768 except when changing month when the increment is 32768 x 2 (65536).

有任何人看到这个二进制日期格式，如何提取正确的日期？

Has anyone seen this binary date format and how can I extract the correct date?

可能剩下的部分日期是时间（小时，分钟，秒）

It is possible that the remaining portion of the date is for time (hours, minutes, seconds)

推荐答案

2008年9月30日

September 30th 2008

1822392319 = 0x6c9f7fff
0x6c = 108 = 2008 (based on 1900 start date)
0x9 = 9 = September
0xf7fff - take top 5 bits = 0x1e = 30

2008年10月1日

October 1st 2008

1822490623 = 0x6ca0ffff
0x6c = 108 = 2008
0xa = 10  = October
0x0ffff  - take top 5 bits = 0x01 = 1

有人猜测剩下的15个一位是什么，如果有的话。

It's anyone's guess what the remaining 15 one-bits are for, if anything.

编辑：以前5位表示：

day_of_month = (value >> 15) & 0x1f

同样：

year = (value >> 24) & 0xff + 1900
month = (value >> 20) & 0x0f

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