gawk 浮点数本地化 [英] gawk floating-point number localization

问题描述

我希望 gawk 使用逗号 , 作为小数点字符来解析数字.所以我将 LC_NUMERIC 设置为 fr_FR.utf-8 但它不起作用:

I want gawk to parse number using comma , as the decimal point character. So I set LC_NUMERIC to fr_FR.utf-8 but it does not work:

echo 123,2 | LC_NUMERIC=fr_FR.utf-8 gawk '{printf ("%.2f
", $1 + 0) }'
123.00

解决方案是指定选项 --posix 或 export POSIXLY_CORRECT=1 但在这种情况下 GNU awk 扩展不可用，例如 delete 或 gensub 函数:

The solution is to specify option --posix or export POSIXLY_CORRECT=1 but in this case the GNU awk extensions are not available, for example delete or the gensub function:

echo 123,2 | LC_NUMERIC=fr_FR.utf-8 gawk --posix '{printf ("%.2f
", $1 + 0) }'
123,20

是否可以在不指定的情况下使用 , 作为小数点的 gawk 解析数字POSIX 选项?

Is it possible to have gawk parsing number with , as decimal point without specifying POSIX option?

推荐答案

您正在寻找的选项是:

--use-lc-numeric

这会强制 gawk 在解析输入数据时使用区域设置的小数点字符.虽然 POSIX 标准要求这个行为，当 --posix 生效时 gawk 会这样做，默认值为遵循传统行为并使用句点作为小数点，即使在句点不是小数点的语言环境中特点.此选项覆盖默认行为，没有--posix 选项的完全严格的严格性.

This forces gawk to use the locale's decimal point character when parsing input data. Although the POSIX standard requires this behavior, and gawk does so when --posix is in effect, the default is to follow traditional behavior and use a period as the decimal point, even in locales where the period is not the decimal point character. This option overrides the default behavior, without the full draconian strictness of the --posix option.

演示:

$ echo 123,2 | LC_NUMERIC=fr_FR.utf-8 awk --use-lc-numeric '{printf "%.2f
",$1}'
123,20

注意:printf 是语句而不是函数，所以括号不是必需的，我不确定你为什么在这里添加零?

Notes: printf is statement not a function so the parenthesis are not required and I'm not sure why you are adding zero here?

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